All categories

3 years ago

Which expression is equivalent to (5^4)^2 A. 25^8 B. 20^2 C. 5^8 D. 5^6

Mathematics

1 answer:

Yuliya22 [10]3 years ago

6 0

Answer:

C. 5^8

to raise a power to another power, multiply the exponents

then multiply thr numbers

then u get 5^8

You might be interested in

Gerry thinks that the points (4,2) and (−1,4) form a line perpendicular to a line with slope 4. Do you agree? Why

faust18 [17]

Answer:

The answer to your question is these lines are not perpendicular.

Step-by-step explanation:

Data

A (4, 2)

B (-1, 4)

slope = m = 4

Perpendicular lines mean that these lines cross and form an angle of 90°. Also, the slope of perpendicular lines is negative reciprocals.

Process

1.- Find the slope of the second line and compare it to the slope given.

slope = $\frac{y2 - y1}{x2 - x1}$

Substitution

slope = $\frac{4 - 2}{-1 - 4}$

Simplification and result

slope = $\frac{-2}{5}$

-2/5 is not a negative reciprocal of 4, so these lines are not perpendicular.

4 0

3 years ago

Julio’s father is four times as old is Julio. The sum of their ages is no less than 55. Find the any quality that can be used to

rosijanka [135]

Answer:

Step-by-step explanation

dont really understand the question but you can see if it is the correct answer

represent julios age as x

represnt julios father age as 4x

so x+4x=5x

5x<55

not sure if this is correct bare that in mind

3 0

3 years ago

Find the distance, in feet, a particle travels in its first 2 seconds of travel, if it moves according to the velocity equation

just olya [345]

Answer:

The particle will travel 6 feet in first 2 seconds.

Step-by-step explanation:

We have been given that a particle moves according to the velocity equation $v(t)= 6t^2-18t+12$ . We are asked to find the distance that the particle will travel in its first 2 seconds.

$s(t)=\int |v(t)|dt$

$s(t)=\int\limits^2_0 |6t^2-18t+12|dt$

Now, we will eliminate the absolute value sign as:

$s(t)=\int\limits^1_0 6t^2-18t+12dt+\int\limits^2_1 -6t^2+18t-12dt$

$s(t)=[\frac{6t^3}{3}-\frac{18t^2}{2}+12t]^1_0 +[\frac{-6t^3}{3}+\frac{18t^2}{2}-12t]^2_1$

$s(t)=[2t^3-9t^2+12t]^1_0 +[-2t^3+9t^2-12t]^2_1$

$s(2)=2(1)^3-9(1)^2+12(1)-(2(0)^3-9(0)^2+12(0))-2(2)^3+9(2)^2-12(2)-(-2(1)^3+9(1)^2-12(1))$

$s(2)=2-9+12-(0)-16+36-24-(-2+9-12)$

$s(2)=5-(0)-4-(-5)$

$s(2)=5-4+5$

$s(2)=6$

Therefore, the particle will travel 6 feet in first 2 seconds.

7 0

3 years ago

Solve for x and y simultaneously x-2y=3. 3x²-5xy-16y=24

GenaCL600 [577]

Hello,

x=3+2y
==> 3(3+2y)²-5(3+2y)y-16y=24
==>2y²+5y+3=0
==>(y=-3/2 and x= 0 or y=-1 and x=1)
sol={(0,-3/2),(1,-1)}

8 0

3 years ago

Read 2 more answers

The scores of the students on a standardized test are normally distributed with a mean of 500 and a standard deviation of 110 wh

Maru [420]

The answer is C.) 59 percent

5 0

3 years ago

Read 2 more answers