Hello,
Let's assume f the age of the father,
s the age of the son.
<span>The age of a father is 2 less than 7 times the age of his son ==> f=7s-2 (1)
</span>
<span>In 3 years, the sum of their ages will be 52 ==>(f+3)+(s+3)=52 (2)
(2)==>f+s+6=52
==>f+s=46 (3)
(3) and (1) ==>7s-2+s=46
==>8s=48
==>s=6
f=46-6=40
</span>
Answer:
2720
Step-by-step explanation:
Given that,
Price of the ticket = 2828.80
To find,
The price before the increase = ?
<u>Procedure</u>:
Let the price before the increase be x
so,
x(100% + 4%) = 2828.80
⇒ 1.04x = 2828.80
⇒ x = 2828.80 ÷ 1.04
∵ x = 2720
Thus, the price before the increase was 2720.
Answer:
230.77 seconds or about 3.85 minutes (2 minutes 50.4 seconds)
Step-by-step explanation:
First I will convert the minutes into seconds to make this a little easier.
1:01.71 would just be 61.71 seconds
400/61.71 is her speed for the first race. (speed is distance/time)
That is approximately 6.5 meters per second
time is distance/speed
1500/6.5= 230.769...
I do not know what you need to round to, but Juliette would take 230.769 seconds to run the 1500 meter race.
Answer:
5^8
----------- which is choice A
4^4
Step-by-step explanation:
(5^2/4)^4
We can separate this (a/b) ^c = a^c / b^c
5^2^5
-------------
4^4
We know that a^b^c = a^(b*c)
5^(2*4)
------------
4^4
5^8
-----------
4^4
Answer: x1 = 10
x2 = 16
x3 = 28
Step-by-step explanation:
