Find the slope of the line through each pair of points (0,1) and (3,0)

2 answers:

6 0

$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{1})\qquad
(\stackrel{x_2}{3}~,~\stackrel{y_2}{0})
\\\\\\
slope = m\implies
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{0-1}{3-0}\implies \cfrac{-1}{3}$

GenaCL600 [577]3 years ago

6 0

Use the slope formula, which is y2-y1 divided by x2-x1. (0,1) is the first pair of points, so it will be x1 and y1. (3,0) will be the 2nd pair of points, so x2 and y2. Plug in the numbers into the formula, so 0-1 divided by 3-0 is -1/3 which is the slope.

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Which expression is equivalent to cos(1.4x) − cos(0.6x)?

givi [52]

Answer:

A. -2sin(x)sin(0.4x)

Step-by-step explanation:

At x=0, the given expression evaluates to zero.

For x near zero, the given expression is slightly negative. You know this because cos(1.4x) decreases faster than cos(0.6x), so their difference will be negative.

Of the answer choices, you can eliminate C and D because they are not zero at x=0. You can eliminate choice B, because it is positive for values of x near zero. The only viable choice is A:

-2sin(x)sin(0.4x)

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Of course, a graphing calculator can help you figure this out. See the attachment. The given expression is plotted using a solid red line; the answer choice A is plotted using blue dots.