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olya-2409 [2.1K]
3 years ago
11

If cosecA = 2 find the value of 1/tanA +sinA /1+cosA

Mathematics
1 answer:
Firlakuza [10]3 years ago
7 0

The final answer is the same as given, which is cosecA= 2.....

hope it helped ☺️

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Which function has zeros at x = -2 and x = 5?
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Answer:

<em>f(x)=x²-3x-10</em>

Step-by-step explanation:

\begin{gathered}f(x) = x {}^{2} - 3x - 10 \\ to \: find \: x \: intercept \:o r \: zero \: substitute \: f(x) = 0\: \\ 0 = x {}^{2} - 3x - 10 \\ x {}^{2} - 3x - 10 = 0 \\ x {}^{2} + 2x - 5x - 10 = 0 \\ x(x + 2) - 5x - 10 = 0 \\ x(x + 2) - 5(x + 2) = 0 \\ (x + 2).(x - 5) = 0 \\ x + 2 = 0 \\ x - 5 = 0 \\ x = - 2 \\ x = 5\end{gathered}

f(x)=x

2

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tofindxinterceptorzerosubstitutef(x)=0

0=x

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