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3 years ago

Find the original price. original price: $? discount: 20% sale price: $75

Mathematics

1 answer:

Nataliya [291]3 years ago

3 0

$93.75
75 / 0.8 = 93.75

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An 18-inch cylindrical cake roll with a radius of 4 inches has been cut

SCORPION-xisa [38]

I think the answer is 36 tin because e the radius is 4

6 0

3 years ago

For their homecoming parade, the students of U-Math have created a colorful banner, 57 meters in length, that is made of two

BartSMP [9]

Answer:

$Length\ of\ the\ long\ piece=40\ meters\\\\Length\ of\ the\ short\ piece=17\ meters$

Step-by-step explanation:

Let be "s" the length in meters of the short piece and "l" the lenght in meters of the long piece.

Set up a system of equations:

$\left \{ {{s+l=57} \atop {s=l-23}} \right.$

Apply the Substitution Method to solve the system. Substitute the second equation into the first equation and solve for "l":

$(l-23)+l=57\\\\2l=80\\\\l=\frac{80}{2}\\\\l=40$

Susbstitute the value of "l" into the second equation in order to find the value of "s". This is:

$s=40-23\\\\s=17$

6 0

3 years ago

2/10 in whole number

Margaret [11]

$\frac{2}{10}$

you just divide 2 by 10, which is

.2

6 0

3 years ago

4x-6 + 2x = 18<br> What’s the answer

solmaris [256]

Answer:

x=4

Step-by-step explanation:

4x-6 + 2x = 18

Combine like terms

6x -6 = 18

Add 6 to each side

6x-6+6 =18+6

6x = 24

Divide each side by 6

6x/6 = 24/6

x =4

6 0

3 years ago

Prove that if one solution for a quadratic equation of theform x2 + bx + c = 0 is rational (where b and c are rational),then the

Elenna [48]

Answer:

The other solution of the given equation x² + bx + c = 0 is also rational number.

Step-by-step explanation:

Here, given: ax² + bx + c = 0 is a quadratic equation

Also, one solution (r) of equation is RATIONAL.

To show: The other solution (s) is also RATIONAL

Now, here: as x² + bx + c = 0

Since r and s are the two given solutions, the given equation can be factorized as:

x² + bx + c = (x -r) (x - s)

Simplifying LHS, we get:

(x -r) (x - s) = x x - r (x) - s (x) + (r)(s)

= x² + x(-r - s) + rs

or, x² + bx + c = x² + x(-r - s) + rs

Comparing the related terms, we get:

b = (-r - s)

⇒ b + s = - r

or, s = -r - b

Now, given : r = Rational and the negative of a rational is also rational.

⇒ -r is also rational

Also, difference of two rational number is also rational.

⇒ -r - b is also rational

⇒ s is a RATIONAL NUMBER

Hence, the other solution of the given equation x² + bx + c = 0 is also rational number.

7 0

3 years ago