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Marrrta [24]
3 years ago
14

How would I do this problem?

Mathematics
1 answer:
kenny6666 [7]3 years ago
7 0

If it's a geometric sequence then:

a_1=27;\ a_2=27\\\\r=\dfrac{a_2}{a_1}\to r=\dfrac{27}{36}=\dfrac{3}{4}=0.75\\\\a_{n+1}=a_nr\\\\a_3=27\cdot0.75=20.25\ CORRECT

We calculate the fourth and fifth term of the sequence:

a_4=a_3r\to a_4=20.25\cdot0.75=15.1875\\\\a_5=a_4r\to a_5=15.1875\cdot0.75=11.390625

Answer:

In year 4 15.1875 animals.

In year 5 11.390625 animals.

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A) what is average rate of change of f(x) over the interval from x=5 to x=9? (table shows values of f(x). graph shows function o
SVETLANKA909090 [29]

Answer:

See below for answers and explanations

Step-by-step explanation:

<u>Part A</u>

The average rate of change of a function over the interval [a,b] is equal to \frac{f(b)-f(a)}{b-a}, hence:

\frac{f(b)-f(a)}{b-a}\\\\\frac{f(9)-f(5)}{9-5}\\\\\frac{14-(-4)}{9-5}\\ \\\frac{14+4}{4}\\ \\\frac{18}{4}\\ \\\frac{9}{2}

Therefore, the average rate of change of f(x) over the interval [5,9] is \frac{9}{2}.

<u>Part B</u>

Do the same thing as in Part A:

\frac{f(b)-f(a)}{b-a}\\ \\\frac{f(1)-f(0.25)}{1-0.25}\\ \\\frac{2-5}{0.75}\\ \\\frac{-3}{0.75}\\ \\-4

Therefore, the average rate of change of g(x) over the interval [0.25,1] is -4.

<u>Part C</u>

To interpret our answer from Part B in terms of the real world it represents, we say that between 0.25 seconds and 1 second, the ball falls at a rate of 4 feet per second (since our average rate of change is negative).

5 0
2 years ago
I need help im gonna post 3 more different questions pls answer them.
Arisa [49]

Answer:

15

Step-by-step explanation:

x³ - (3 + x)²

4³ - (3 + 4)²

8 0
3 years ago
Complete the square x^2+45=-14x
Rom4ik [11]

2
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x
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8 0
3 years ago
4 is added to three times a certain number the result is not more than when twice that number is added to 10 find the possible r
malfutka [58]
4
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3 0
3 years ago
The line inside this circle is its
Alex777 [14]
The answer will be (D)
Hope this helps
May i plz have brainliest?
6 0
3 years ago
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