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3 years ago

True or False: The value of r represents the reference angle when plotting a point in polar coordinates.

Mathematics

1 answer:

timama [110]3 years ago

4 0

<span>The value of r represents the reference angle when plotting a point in polar coordinates.
False
</span>

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Find the distance between points (2, 9) and (5, 4) to the nearest tenth

Troyanec [42]

Answer:

$Distance = 5.8$

Step-by-step explanation:

$d=\sqrt{(4-9)^{2} } { (5-2)} ^{2} \\$

$d = -5^{2} + 3^{2}$

$d= 25 + 9$

$d= \sqrt{34}$

$distance = 5.8$

3 0

3 years ago

The following equation is being multiplied by the LCD. Complete the multiplication to eliminate the denominators

frosja888 [35]

Answer:

$(x+2)(x-2) -1(3x)=(x-3)(x-2)$

Step-by-step explanation:

x+2/3x - 1/x-2 = x-3/3x

$\frac{x+2}{3x}-\frac{1}{x-2}=\frac{x-3}{3x}$

LCD is (3x)(x-2). so we multiply the whole equation by LCD

$(3x)(x-2)(\frac{x+2}{3x}-\frac{1}{x-2}=\frac{x-3}{3x})$

We multiply each term by LCD

$(3x)(x-2)(\frac{x+2}{3x})-(3x)(x-2)(\frac{1}{x-2})=(3x)(x-2)(\frac{x-3}{3x})$

$(x+2)(x-2) -1(3x)=(x-3)(x-2)$

4 0

3 years ago

Read 2 more answers

H(x)=-4x+3;when h(x)=11

liberstina [14]

To solve this, since you know that h(x) is 11 and that it also equals -4x+3, you set them equal to one another which would look like this: 11=-4x+3.
Then, to solve for x, which is what I am assuming the question is asking, you would subtract 3 from both sides to isolate -4x, which would result in this:
-4x=8
Now, to solve for x, divide both sides by -4, and you get your answer which is x=-2

3 0

3 years ago

What is the amplitude of sin ?

sp2606 [1]

You haven't provided a graph or equation so I will tell the simplified meaning of amplitude instead.

Amplitude, is basically a distance from midline/baseline to the maximum or minimum point.

For sine function, can be written as:

$\displaystyle \large{ y = A \sin(bx - c) + d}$

A = amplitude
b = period = 2π/b
c = horizontal shift
d = vertical shift

I am not able to provide an attachment for an easy view but I will try my best!

We know that amplitude or A is a distance from baseline/midline to the max-min point.

Let's see the example of equation:

$\displaystyle \large{y = 2 \sin x}$

Refer to the equation above:

Amplitude = 2
b = 1 and therefore, period = 2π/1 = 2π
c = 0
d = 0

Thus, the baseline or midline is y = 0 or x-axis.

You can also plot the graph on desmos, y = 2sinx and you will see that the sine graph has max points at 2 and min points at = -2. They are amplitude.

So to conclude or say this:

If Amplitude = A from y = Asin(x), then the range of function will always be -A ≤ y ≤ A and have max points at A; min points at -A.

6 0

3 years ago

Can someone help me with this math problem.

Vikentia [17]

Answer:

Its 11.50 per shirt

Step-by-step explanation:

We know this because if you do 46/4 = 11.50 and if you do 80.50/7 = 11.50 as well

4 0

3 years ago

Read 2 more answers