x=71
-46+x=25
add 46 to both sides (you do the inverse!)
x=71
Answer:
x = 13
Explanation:
3(2x−5)−4x=11
- Step 1: Simplify both sides of the equation
3(2x−5)−4x=11
(3)(2x)+(3)(−5)+−4x=11 (Distribute)
6x+−15+−4x=11
(6x+−4x)+(−15)=11 (Combine Like Terms)
2x+−15=11
2x−15=11
- Step 2: Add 15 to both sides
2x−15+15=11+15
2x=26
- Step 3: Divide both sides by 2
2x / 2 = 26 / 2
x = 13
Answer:
$14,999.
Step-by-step explanation:
Logic....
Answer:
The ira will contain $228,278.05 when he retires at age 65. This is 6.04 times the amount of money he deposited.
Step-by-step explanation:
In order to solve this problem, we can make use of the following formula:
![FV=PMT[\frac{(1+i)^{n}-1}{i}]](https://tex.z-dn.net/?f=FV%3DPMT%5B%5Cfrac%7B%281%2Bi%29%5E%7Bn%7D-1%7D%7Bi%7D%5D)
Where:
FV= Future value of the ira
PMT= the amount of money you deposit each month
i= is the interest rate per period
n=number of periods
in this case we will assume the interest will be compounded each month.
So:
FV this is what we need to know.
PMT= $75 the amount he will deposit each month
t = 42 years,
this is 65-23=42
n=42 years * 12 months/year = 504 months
i=0.07/12
So we can now use the given formula:
![FV=PMT[\frac{(1+i)^{n}-1}{i}]](https://tex.z-dn.net/?f=FV%3DPMT%5B%5Cfrac%7B%281%2Bi%29%5E%7Bn%7D-1%7D%7Bi%7D%5D)
![FV=75[\frac{(1+\frac{0.07}{12})^{504}-1}{\frac{0.07}{12}}]](https://tex.z-dn.net/?f=FV%3D75%5B%5Cfrac%7B%281%2B%5Cfrac%7B0.07%7D%7B12%7D%29%5E%7B504%7D-1%7D%7B%5Cfrac%7B0.07%7D%7B12%7D%7D%5D)
So we get:
FV=$228,278.05
which is the amount of money he will have after 42 years.
In total, he deposited:
$75*504months = $37,800
so he will have:
times the amount of money he deposited throughout this time.
164.00 is your answer
Hope it helps!
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