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tresset_1 [31]
3 years ago
14

Consider an experiment involving the game spinner pictured below. A 20 trial experiment is conducted to determine the probabilit

y of landing on blue. Assume the spinner is perfectly balanced and the probability of each color is the same. What is the probability of landing on blue 5 times?
Mathematics
1 answer:
Nookie1986 [14]3 years ago
4 0

Answer: 1/4

Step-by-step explanation:

To determine the probability of landing on blue, you divide by the total number of spins.

In this experiment, the probability of the spinner landing on blue after 20 spins would be 15%.

This makes the probability of landing on blue to be:

Pr (landing on blue) / Pr (total trials) = 5/20

This gives 1/4

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Whats the value of 3x^2 + 5x when x=3 . show woro please if you can.
lubasha [3.4K]

Answer:

42

Step-by-step explanation:

3x^2 +5x

Let x=3

3(3)^2 +5(3)

3*9 +15

27+15

42

6 0
3 years ago
In class A, John got 85 for his first test John's class mean was 75 and standard deviation was 5. In class B, Kathy got 80 in he
ivanzaharov [21]

Answer:

b. Kathy

Step-by-step explanation:

We compare each of their score by how far away from the mean when in term of the standard deviation. Using the following formula

\frac{x - \mu}{\sigma}

For John he is (85 - 75)/5 = 2.

For Kathy she is (80 - 50)/10 = 3.

Since Kathy is 3 standard deviation better than her class' average, while John is only 2's. We conclude that Kathy did better.

6 0
3 years ago
What’s 9x9cause I’m having troubles
photoshop1234 [79]

Answer: The answer is 81.

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3 years ago
The probability distribution for the rate of return on an investment is
babymother [125]

Answer:

a)0.7

b) 10.03

c)  0.0801

Step-by-step explanation:

Rate of return   Probability

9.5                           0.1

9.8                           0.2

10                             0.3

10.2                          0.3

10.6                          0.1

a.

P(Rate of return is at least 10%)=P(R=10)+P(R=10.2)+P(R=10.6)

P(Rate of return is at least 10%)=0.3+0.3+0.1

P(Rate of return is at least 10%)=0.7

b)

Expected rate of return=E(x)=sum(x*p(x))

Rate of return(x)   Probability(p(x))    x*p(x)

9.5                           0.1                       0.95

9.8                           0.2                      1.96

10                             0.3                        3

10.2                          0.3                        3.06

10.6                          0.1                       1.06

Expected rate of return=E(x)=sum(x*p(x))

Expected rate of return=0.95+1.96+3+3.06+1.06=10.03

c)

variance of the rate of return=V(x)=sum(x^2p(x))-[sum(x*p(x))]^2

Rate of return(x)   Probability(p(x))    x*p(x)    x²*p(x)

9.5                           0.1                       0.95       9.025

9.8                           0.2                      1.96         19.208

10                             0.3                       3             30

10.2                          0.3                       3.06        31.212

10.6                          0.1                       1.06         11.236

sum[x²*p(x)]=9.025+19.208+30+31.212+11.236=100.681

variance of the rate of return=V(x)=sum(x²*p(x))-[sum(x*p(x))]²

variance of the rate of return=V(x)=100.681-(10.03)²

variance of the rate of return=V(x)=100.681-100.6009

variance of the rate of return=V(x)=0.0801

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