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egoroff_w [7]
3 years ago
12

What is the sum of m A and m B if angles A and B are supplementary?

Mathematics
2 answers:
jok3333 [9.3K]3 years ago
6 0

Answer:

following

Step-by-step explanation:

iragen [17]3 years ago
4 0

Answer:

D) 180°

Step-by-step explanation:

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HELPPPPP PLEASE. NEED IT ASAP
MAXImum [283]

Answer:

48

Step-by-step explanation:

30/3=10 for all in 1 week

10/5=2 each person in a meal

Since all eat the same amount, 2x3=6 per meal. 6 hot dogs x 8 meals= 48 hot dogs in total

Hope this helped XD

3 0
3 years ago
What equations are equivalent to 3(5x+4)=12x+18
Vladimir79 [104]

Answer:

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
An independent-measures research study was used to compare two treatment conditions with n= 12 participants in each treatment. T
Maurinko [17]

Answer:

(a) The data indicate a significant difference between the two treatments.

(b) The data do not indicate a significant difference between the two treatments.

(c) The data indicate a significant difference between the two treatments.

Step-by-step explanation:

Null hypothesis: There is no difference between the two treatments.

Alternate hypothesis: There is a significant difference between the two treatments.

Data given:

M1 = 55

M2 = 52

s1^2 = 8

s2^2 = 4

n1 = 12

n2 = 12

Pooled variance = [(n1-1)s1^2 + (n2-1)s2^2] ÷ (n1+n2-2) = [(12-1)8 + (12-1)4] ÷ (12+12-2) = 132 ÷ 22 = 6

Test statistic (t) = (M1 - M2) ÷ sqrt [pooled variance (1/n1 + 1/n2)] = (55 - 52) ÷ sqrt[6(1/6 + 1/6)] = 3 ÷ 1.414 = 2.122

Degree of freedom = n1+n2-2 = 12+12-2 = 22

(a) For a two-tailed test with a 0.05 (5%) significance level and 23 degrees of freedom, the critical values are -2.069 and 2.069.

Conclusion:

Reject the null hypothesis because the test statistic 2.122 falls outside the region bounded by the critical values.

(b) For a two-tailed test with a 0.01 (1%) significance level and 23 degrees of freedom, the critical values are -2.807 and 2.807.

Conclusion:

Fail to reject the null hypothesis because the test statistic 2.122 falls within the region bounded by the critical values.

(c) For a one-tailed test with 0.05 (5%) significance level and 23 degrees of freedom, the critical value is 1.714.

Conclusion:

Reject the null hypothesis because the test statistic 2.122 is greater than the critical value 1.714.

6 0
3 years ago
Look at the system of equations below<br> Sy= -2x +3<br> 1 4x – 3y = 11
kompoz [17]

Answer:

(2,-1)

y= -1

x= 2

Step-by-step explanation:

y= -2x+3

4x-3y=11

substitute the value of y into an equation

4x-3(-2x+3)=11

distribute by multiplying numbers in parenthesis by -3

4x+6x-9=11

add 4x to 6x

10x-9=11

add 9 from both sides

10x=20

divide both sides by 10

x=2

substitute the value of x into an equation

y= -2•2+3

multiply -2 to 2

y= -4+3

add -4 to 3 but 4 is negative, so subtract

y= -1

-----------

(2,-1)

-----------

3 0
3 years ago
Evaluate 5a3 + 3b4 when a 4 and b= - 5​
valkas [14]
5a^3 + 3b^4

insert the numbers into the equation.

5(4)^3 + 3(-5)^4

evaluate

5(64) + 3(625)

evaluate

320 + 1875

the solution is:

2195
5 0
3 years ago
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