See the attached picture to better understand the problem
we know that
in the right triangle ABC
cos 70=adjacent side angle 70/hypotenuse
adjacent side angle 70=BC----> <span>distance between the ladder and the tree trunk
hypotenuse=AC------> 15 ft
cos 70=BC/AC-------> solve for BC
BC=AC*cos 70------> BC=15*cos 70-----> BC=5.13 ft
the answer isthe </span>
distance between the ladder and the tree is 5.13 ft<span>
</span>
Answer:
Translate 4 units to the left and reflect over the x-axis
Step-by-step explanation: hope this helps :)
Answer:
<u><em>73.72 ft Squared</em></u>
Step-by-step explanation:
First you need to find the area of the rectangle the area of rectangle is 8x10=80. Then You take that 80=3.14x2. then you find the area by dividing it. so...
1.) 80=3.14x2
3.14x2=6.28 <u> 80=6.28 </u> (Then you divide 6.28 by 80)
80 80
This is not math
Explation:
Answer:
- 1. First blank: <u>∠ACB ≅ ∠E'C'D'</u>
- 2. Second blank: <u>translate point E' to point A</u>
Therefore, the answer is the third <em>option:∠ACB ≅ ∠E'C'D'; translate point D' to point B</em>
Explanation:
<u>1. First blank: ∠ACB ≅ ∠E'C'D'</u>
Since segment AC is perpendicular to segment BD (given) and the point C is their intersection point, when you reflect triangle ECD over the segment AC, you get:
- the image of segment CD will be the segment C'D'
- the segment C'D' overlaps the segment BC
- the angle ACB is the same angle E'C'D' (the right angle)
Hence: ∠ACB ≅ ∠E'C'D'
So far, you have established one pair of congruent angles.
<u>2. Second blank: translate point D' to point B</u>
You need to establish that other pair of angles are congruent.
Then, translate the triangle D'C'E' moving point D' to point B, which will show that angles ABC and E'D'C' are congruents.
Hence, you have proved a second pair of angles are congruent.
The AA (angle-angle) similarity postulate assures that two angles are similar if two pair of angles are congruent (because the third pair has to be congruent necessarily).
