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jeka57 [31]
3 years ago
15

What type of reaction is depicted by this equation?

Chemistry
1 answer:
const2013 [10]3 years ago
5 0
It is a decomposition reactions
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Which of the following is an example of how a scientist might use a model?
tiny-mole [99]
I am thinking it is c) A microscope is used to magnify a group of cells on a slide. 
7 0
3 years ago
The solubility of o2 at 20c is 1.38 x10^-3. the partial presure of o2 in the air at sea level is 0.27 atm. using henery;s law, c
netineya [11]

<u>Answer:</u> The solubility of oxygen at 682 torr is 4.58\times 10^{-3}M

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{A}=K_H\times p_{A}

Or,

\frac{C_{1}}{C_{2}}=\frac{p_{1}}{p_2}

where,

C_1\text{ and }p_1 are the initial concentration and partial pressure of oxygen gas

C_2\text{ and }p_2 are the final concentration and partial pressure of oxygen gas

We are given:

Conversion factor used:  1 atm = 760 torr

C_1=1.38\times 10^{-3}M\\p_1=0.27atm\\C_2=?\\p_2=682torr=0.897atm

Putting values in above equation, we get:

\frac{1.38\times 10^{-3}}{C_2}=\frac{0.27atm}{0.897atm}\\\\C_2=\frac{1.38\times 10^{-3}\times 0.897atm}{0.27atm}=4.58\times 10^{-3}M

Hence, the solubility of oxygen gas at 628 torr is 4.58\times 10^{-3}M

4 0
3 years ago
Report the number 315.05 to 3 significant figures.
emmainna [20.7K]

Answer:

315.

Explanation:

Hello.

In this case, since the given number has five significant figures as the zero is to the right of the first nonzero digit (3), if it is required to report it with three significant figures, it is necessary to "cut" it at the first five without any rounding since the subsequent zero is less than five.

Thus the number turns out:

315

Best regards.

5 0
3 years ago
What ion (cation or anion and charge) do the halogen group (17) form to fulfill the octet
Dafna11 [192]

Answer:

option B= anion (-1)

Explanation:

The halogens are present in the P- block of periodic table. There are thirty five elements present in p-block. The halogens are present in group seventeen. Their are seven electrons are present in valance sheet. All halogens require one electron to complete the octet and form anion carry -1 charge.

Halogens include following elements:

Fluorine, chlorine, bromine, iodine and astatine.

The halogens mostly form single bond with the other elements by gaining one electron and -1 charge. These are most reactive non-metals.

Properties of some halogen elements:

Fluorine:

1. It is yellow in color.

2. It is flammable gas.

3. It is highly corrosive.

4. Fluorine has pungent smell.

5. It's reactions with all other elements are vigorous except neon, oxygen, krypton and helium.  

Chlorine:

1. It is greenish-yellow irritating gas.

2. Its melting point is 172.2 K.

3. Its boiling point is 238.6 K.

4. It is disinfectant and can kill the bacteria.

5. It is also used in manufacturing of paper, paints and textile industries.

Iodine:

1. It is present in solid form.

2. It is crystalline in nature.

3. It is very corrosive and has pungent odor.

4. It can not react with oxygen and nitrogen.

6 0
3 years ago
How many grams of sulfur are needed to react completely with 246 g of mercury to form hgs?
iren [92.7K]

The reaction between mercury (Hg) and sulfur (S) to form HgS is:

Hg + S ------------- HgS

Therefore: 1 mole of Hg reacts with 1 mole of S to form 1 mole of HgS

The given mass of Hg = 246 g

Atomic mass of Hg = 200.59 g/mol

# moles of Hg = 246 g/ 200.59 gmol-1 = 1.226 moles

Based on the reaction stoichiometry,

# moles of S that would react = 1.226 moles

Atomic mass of S = 32 g/mol

Therefore, mass of S = 1.226 moles*32 g/mole = 39.23 g

39.2 g of sulfur would be needed to react completely with 246 g of Hg to produce HgS

5 0
3 years ago
Read 2 more answers
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