For each of the following balanced equations, calculate how many grams of each product would be produced by complete reaction of
15.0 g of the reactant
indicated in boldface. (*)
a. *2BC13(s)* + 3H2(g) -> 2B(s) + 6HCl(g)
b. *2Cu S(s)* + 302(g) → 2Cu2O(s) + 2SO2(g)
C. 2Cu2O(s) + *Cu2S(s)* -> 6Cu(s) + SO2(g)
d. CaCO3(s) + *SiO2(s)* → CaSiO3(s) + CO2(g)
indicated in boldface. (*)
a. *2BC13(s)* + 3H2(g) -> 2B(s) + 6HCl(g)
b. *2Cu S(s)* + 302(g) → 2Cu2O(s) + 2SO2(g)
C. 2Cu2O(s) + *Cu2S(s)* -> 6Cu(s) + SO2(g)
d. CaCO3(s) + *SiO2(s)* → CaSiO3(s) + CO2(g)
1 answer:
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Answer:
8.34
Explanation:
1) how much moles of NH₃ are in the reaction;
2) how much moles of H₂ are in the reaction;
3) the required mass of the H₂.
all the details are in the attachment; the answer is marked with red colour.
Note1: M(NH₃) - molar mass of the NH₃, constant; M(H₂) - the molar mass of the H₂, constant; ν(NH₃) - quantity of NH₃; ν(H₂) - quantity of H₂.
Note2: the suggested solution is not the shortest one.
