For each of the following balanced equations, calculate how many grams of each product would be produced by complete reaction of
15.0 g of the reactant
indicated in boldface. (*)
a. *2BC13(s)* + 3H2(g) -> 2B(s) + 6HCl(g)
b. *2Cu S(s)* + 302(g) → 2Cu2O(s) + 2SO2(g)
C. 2Cu2O(s) + *Cu2S(s)* -> 6Cu(s) + SO2(g)
d. CaCO3(s) + *SiO2(s)* → CaSiO3(s) + CO2(g)
indicated in boldface. (*)
a. *2BC13(s)* + 3H2(g) -> 2B(s) + 6HCl(g)
b. *2Cu S(s)* + 302(g) → 2Cu2O(s) + 2SO2(g)
C. 2Cu2O(s) + *Cu2S(s)* -> 6Cu(s) + SO2(g)
d. CaCO3(s) + *SiO2(s)* → CaSiO3(s) + CO2(g)
1 answer:
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Answer : The volume of pure diamond is
Explanation : Given,
Density of pure carbon in diamond =
Moles of pure diamond = 23.7 moles
Molar mass of carbon = 12 g/mol
First we have to calculate the mass of carbon or pure diamond.
Molar mass of carbon = 12 g/mol
Now we have to calculate the volume of carbon or pure diamond.
Formula used:
Now putting all the given values in this formula, we get:
Volume =
As we know that:
So,
Volume =
Volume =
Therefore, the volume of pure diamond is
P = 11.133 atm (purple)
T = -236.733 °C(yellow)
n = 0.174 mol(red)
<h3>Further explanation </h3>Some of the laws regarding gas, can apply to ideal gas (volume expansion does not occur when the gas is heated),:
- Boyle's law at constant T, P = 1 / V
- Charles's law, at constant P, V = T
- Avogadro's law, at constant P and T, V = n
So that the three laws can be combined into a single gas equation, the ideal gas equation
In general, the gas equation can be written
where
P = pressure, atm
V = volume, liter
n = number of moles
R = gas constant = 0.08206 L.atm / mol K
T = temperature, Kelvin
To choose the formula used, we refer to the data provided
Because the data provided are temperature, pressure, volume and moles, than we use the formula PV = nRT
- Purple box
T= 10 +273.15 = 373.15 K
V=5.5 L
n=2 mol
- Yellow box
V=8.3 L
P=1.8 atm
n=5 mol
- Red box
T = 12 + 273.15 = 285.15 K
V=3.4 L
P=1.2 atm