Answer:
16 g/L
Explanation:
Given that:-
Mass of sucrose added = 1.2 g
Volume of water = 75 mL = 0.075 L ( 1mL = 0.001 L )
%w/v is defined as the mass of the solution in 1 L of the solution.
So,
For each of the following balanced equations, calculate how many grams of each product would be produced by complete reaction of
15.0 g of the reactant
indicated in boldface. (*)
a. *2BC13(s)* + 3H2(g) -> 2B(s) + 6HCl(g)
b. *2Cu S(s)* + 302(g) → 2Cu2O(s) + 2SO2(g)
C. 2Cu2O(s) + *Cu2S(s)* -> 6Cu(s) + SO2(g)
d. CaCO3(s) + *SiO2(s)* → CaSiO3(s) + CO2(g)
indicated in boldface. (*)
a. *2BC13(s)* + 3H2(g) -> 2B(s) + 6HCl(g)
b. *2Cu S(s)* + 302(g) → 2Cu2O(s) + 2SO2(g)
C. 2Cu2O(s) + *Cu2S(s)* -> 6Cu(s) + SO2(g)
d. CaCO3(s) + *SiO2(s)* → CaSiO3(s) + CO2(g)
1 answer:
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