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Pie
3 years ago
8

C5h12 formula mass= molar mass=

Chemistry
1 answer:
mojhsa [17]3 years ago
8 0
C5H12 = 12 x 5 + 1 x 12 => 72 g/mol
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What are the four types of biological molecules and their main function in the human body?
Flauer [41]

Answer:

There are four major classes of biological macromolecules (carbohydrates, lipids, proteins, and nucleic acids)

Explanation:

There are four major classes of biological macromolecules (carbohydrates, lipids, proteins, and nucleic acids), and each is an important component of the cell and performs a wide array of functions. ... Biological macromolecules are organic, meaning that they contain carbon.

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3 years ago
Explain how chemists overcome the problem of low yield In industry
mrs_skeptik [129]

High temperature and pressure produce the highest rate of reaction. However, this must be balanced with the high cost of the energy needed to maintain these conditions. Catalysts increase the rate of reaction without affecting the yield. This can help create processes which work well even at lower temperatures.

I hope this helps you.

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3 years ago
Classify each of the following particulate level illustrations as a representation of either a pure substance, a homogeneous mix
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Answer:

The classification and illustrations are attached in the drawing.

Explanation:

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4 0
3 years ago
During the chemical reaction given below 21.71 grams of each reagent were allowed to react. Determine how many grams of the exce
swat32

Answer: 16.32 g of O_2 as excess reagent are left.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} SO_2=\frac{21.71g}{64g/mol}=0.34mol

\text{Moles of} O_2=\frac{21.71g}{32g/mol}=0.68mol

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)  

According to stoichiometry :

2 moles of SO_2 require = 1 mole of O_2

Thus 0.34 moles of SO_2 will require=\frac{1}{2}\times 0.34=0.17moles  of O_2

Thus SO_2 is the limiting reagent as it limits the formation of product and O_2 is the excess reagent.

Moles of O_2 left = (0.68-0.17) mol = 0.51 mol

Mass of O_2=moles\times {\text {Molar mass}}=0.51moles\times 32g/mol=16.32g

Thus 16.32 g of O_2 as excess reagent are left.

3 0
2 years ago
HURRYYY !!!! What radioactive isotope produces Aluminum-13 by beta decay
fgiga [73]

Answer:

I DONT KNOW SORRY

Explanation:

7 0
2 years ago
Read 2 more answers
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