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FinnZ [79.3K]
4 years ago
14

Ahmed wrote the two expressions below.

Mathematics
2 answers:
tensa zangetsu [6.8K]4 years ago
5 0

Answer:

d. put an equal sign between the two expressions, and solve for x

Step-by-step explanation:

The two expressions are :

\frac{3}{4} (8x+4) and (6x+1)

We can say that \frac{3}{4} (8x+4) is LHS and we have to solve it to become equal to RHS or (6x+1)

Now we have to tell procedure can Ahmed follow to determine if the two expressions are equivalent. For equivalent equations we put an equal sign between the expressions and solve them.

Solving LHS or \frac{3}{4} (8x+4)

\frac{3}{4}*4(2x+1)

Cancelling out 4 we get:

6x+1 or the RHS

Therefore, option D is the correct answer.

Vsevolod [243]4 years ago
3 0
Put an equal sign between the two expressions, and solve for x
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x=-2 y=0

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Kitty [74]

Answer:   (-2, 5) and (2, -3)

<u>Step-by-step explanation:</u>

Graph the line y = -2x + 1 (which is in y = mx + b format) by plotting the y-intercept (b = 1) on the y-axis and then using the slope (m = -2) to plot the second point by going down 2 and right 1 unit from the first point:

        y - intercept = (0, 1)            2nd point = ( -1, 1).

Graph the parabola y = x² - 2x - 3 by first plotting the vertex and then plotting the y-intercept (or some other point):

y = x^2-2x-3\quad \rightarrow \quad a=1,\ b=-2,\ c=-3\\\\\text{axis of symmetry:}\ x = \dfrac{-b}{2a}\ \longrightarrow \ x=\dfrac{-(-2)}{2(1)}=\dfrac{2}{2}=1\\\\\text{y-value of vertex:}\ f(1) = (1)^2-2(1)-3\quad \longrightarrow \quad y = 1 - 2 - 3=-4\\\\\text{y-intercept:}\ f(0)= (0)^2-2(0)-3\ \longrightarrow \ y=0 - 0 - 3 = -3 \\

         vertex = (1, -4)                2nd point (y-intercept) = (0, -3)


<em>see attached</em> - the graphs intersect at two points:  (-2, 5) and (2, -3)


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