Ahmed wrote the two expressions below.
2 answers:
Answer:
d. put an equal sign between the two expressions, and solve for x
Step-by-step explanation:
The two expressions are :
and
We can say that is LHS and we have to solve it to become equal to RHS or
Now we have to tell procedure can Ahmed follow to determine if the two expressions are equivalent. For equivalent equations we put an equal sign between the expressions and solve them.
Solving LHS or
Cancelling out 4 we get:
or the RHS
Therefore, option D is the correct answer.
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The standard form of a quadratic equation is 
, while the vertex form is:
, where (h, k) is the vertex of the parabola.
What we want is to write
as
First, we note that all the three terms have a factor of 3, so we factorize it and write:
.
Second, we notice that
are the terms produced by 
, without the 9. So we can write:
, and substituting in we have:
![\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11]](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%20y%3D3%28x%5E2-6x-2%29%3D3%5B%28x-3%29%5E2-9-2%5D%3D3%5B%28x-3%29%5E2-11%5D)
.
Finally, distributing 3 over the two terms in the brackets we have:
![y=3[x-3]^2-33](https://tex.z-dn.net/?f=y%3D3%5Bx-3%5D%5E2-33)
.
Answer:
What we want is to write
First, we note that all the three terms have a factor of 3, so we factorize it and write:
Second, we notice that
Finally, distributing 3 over the two terms in the brackets we have:
Answer:
Answer:
Step-by-step explanation:
Pay attention to the two tick marks. This indicates that those sides are congruent to each other and so will the angles on the bottom and top. Therefore, we can set up the equation and solve for x: