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motikmotik
2 years ago
14

Mathhhhhhhhhhhhhhhhhhhhhhhhhhh

Mathematics
1 answer:
Thepotemich [5.8K]2 years ago
3 0

Answer:

the last option.........

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I need help. once again. bahahaha
katrin [286]

Answer:

letters d. and e.

5 0
3 years ago
Consider independently rolling two fair dice, one red and the other green. Let A be the event that the red die shows 3 dots, B b
max2010maxim [7]

Answer:

A & B are independent events. A & C, B & C are not independent events.

Step-by-step explanation:

Independent Events are the events, whose occurrences are completely unrelated to each other.

Event A 'Red dice getting 3' & Event B 'Green die getting 4' ; are unrelated to each other. The numbers on red dice & on green dice are not dependent on each other.

Event C 'Red & Green dice numbers showing sum = 7' is dependent on the numbers coming on red & green dice , i.e events A & events B respectively. So, event C is dependent on both events A & B.

4 0
3 years ago
The graph below shows the number of pages that Victor has left to read in his book at the end of the day over seven days.
Mashutka [201]

Answer:

it A

Step-by-step explanation:

i got it right :)

5 0
3 years ago
Read 2 more answers
What is the simplified form of the expression? 6/√5−√2
tester [92]

Answer:

The expression can be simplified into 2\,\sqrt{5} +2\sqrt{2}

with no square roots in the denominator

Step-by-step explanation:

We are considering the expression  \frac{6}{\sqrt{5}-\sqrt{2}  }  which I believe is what you wanted to type in your question.

The idea behind simplification of the expression, is normally associated with the rationalization of the denominator by eliminating irrational numbers from it. This means to get rid of any "irrational" number expression (like in this example, the square root of non-perfect square numbers (\sqrt{5}\,\,\,and \,\,\sqrt{2}).

We proceed by writing this quotient in an equivalent form by multiplying its numerator and its denominator by what is called the "conjugate" of the denominator. In our case, multiply by " (\sqrt{5} +\sqrt{2}) ", because such product will allow the denominator to become a rational number:

\frac{6}{\sqrt{5}-\sqrt{2}  }\,*\,\frac{(\sqrt{5}+\sqrt{2} )}{(\sqrt{5}+\sqrt{2}) } =\frac{6\,(\sqrt{5}\,+\,\sqrt{2} )}{\sqrt{5}^2-\sqrt{2}^2 }=\frac{6\,(\sqrt{5}\,+\,\sqrt{2} )}{3}=2\,\sqrt{5} +2\sqrt{2}

where we find all square roots eliminated from the denominator

5 0
3 years ago
Work out the second zen of an exterior and an interior angle of a regular 16 sided polygon
Dimas [21]

Answer:Idk im not profech

Step-by-step explanation:

5 0
3 years ago
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