2 years ago

(4y+5)(7y-3)= what is the solution to this problem

Mathematics

1 answer:

nikdorinn [45]2 years ago

6 0

Answer:

all work is pictured/shown

You might be interested in

Find a number that when subtracted from the numerator of 13/8 and added to the denominator of 13/8 results in fraction equivalen

mariarad [96]

The answer should be 6/15

3 0

2 years ago

Can someone please help me with these two questions! :( ill mark u as brainlest

Maslowich

Answer:

1.A by SSS axiom

2.F as angle A is 62*

4 0

2 years ago

Sarah's age is four more than twice her brothers age. Write two equivalent algebraic equations that can be used to find their ag

marissa [1.9K]

Answer:

Step-by-step explanation:

Let her brother's age be x

Sarah is 2x + 4

3 0

3 years ago

Solve the system by substitution<br> 10x=y<br><br> 2x+y=-24

masha68 [24]

Answer: x=-2

Y= -20

Step-by-step explanation

You replace the y in the second equation with 10x. This is because it says 10x=y

2x+10x=12x so you put that

12x=-24

To get x by its self you divide by 12.

-24 divided by 12 is -2.

Now you plug in -2 to either equation as y. I chose the first one because it's easier.

10(-2)=y

-20=y

8 0

2 years ago

There are 200 students in the 8th grade class at Alleghany Middle School. Of these students, 8% play basketball and 14% play soc

sergeinik [125]

Answer:

The probability that a student plays either basketball or soccer is 19% or 0.19.

Step-by-step explanation:

Let A be the event that student play basketball and B be the event that student play soccer.

$P(A)=8\%$

$P(B)=14\%$

It is given that 6 students play on both teams.

$P(A\cap B)=\frac{6}{200}\times 100=3\%$

We have to find the probability that a student plays either basketball or soccer.

$P(A\cup B)=P(A)+P(B)-(A\cap B)$

$P(A\cup B)=8\%+14\%-3\%$

$P(A\cup B)=19\%$

Therefore the probability that a student plays either basketball or soccer is 19% or 0.19.

6 0

3 years ago