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levacccp [35]
4 years ago
15

ARI

Mathematics
1 answer:
umka21 [38]4 years ago
4 0
0 or if maybe another 0 for two ZER0s
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Y=3x, x+y=52<br> Solve by subtracting
Nesterboy [21]

Answer:

x=13,y=39

Step-by-step explanation:

y=3x,x+y=52

x+3x=52

4x=52

x=52/4

x=13

y=3(13)

y=39

5 0
3 years ago
What is the area of the figure shown below? giving brainly!!
siniylev [52]

Answer:

4073.76

Step-by-step explanation:

3 0
3 years ago
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Percy said that any real number for k would cause the system of equations to have no solution. Explain the error in Percy’s stat
MatroZZZ [7]

Answer:

Except k=7, any real number for k would cause the system of equations to have no solution.

Step-by-step explanation:

In general a system of equations can be represented as ax+by=c and dx+ey=f. In order this system of equations to have NO SOLUTIONS a/d=b/a≠c/f. In our example a=6, b=4, c=14, d=3, e=2 and f=k. To apply the formula above, 6/3=4/2≠14/k. Hence k≠7. It can be concluded that except k=7, any real number for k would cause the system of equations to have no solutions.

Just for information, if k=7 the system will have infinitely many solutions.

5 0
3 years ago
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Find -5A+4B<br><br><br> please only answer if yk the answer
pishuonlain [190]

Answer:

D is the answers for the question

Step-by-step explanation:

please mark me as brainlest

5 0
3 years ago
The product of 6 and 11 written as an algebraic expression
docker41 [41]

Answer:

(2×3)¹

(11×1)¹

Step-by-step explanation:

2×3=6 so 2 to the power 1 is 2 and 3 to the power 1 is 3 so 2×3=6

11×1=11 so 11 to the power 1 is 11 and 1 to the power 1 is 1 so 11×1 =11

3 0
2 years ago
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