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UNO [17]
3 years ago
12

A linear function that represents the number of hot dogs purchased at a football game is compared to a different linear function

that represents the time left in the game. Describe the key features of the functions that are needed to determine if these lines intersect.
Mathematics
1 answer:
Vsevolod [243]3 years ago
5 0

Answer:

Key features: the functions can not be parallels, this means that their respective slopes can not be equal or multiple to the other

Step-by-step explanation:

Take for instance 2 linear functions,  and

If they intersect in some point in the space, say that is

Then (x1,y1)=(x3,y3), (x2.y2)= (x3,y3)

So, we can compare the two functions and get the following result;

It tells us that if M=m, we get an error, meaning that the functions are in fact parallels and there is no way that they meet in some point.

hope this helps!

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A square has the same length on all of it's sides. The area of a square is side times side. So it's 2.2×2.2=?
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Distribute <br>(x-6)(x-7)<br><br>a) x^2-13x-15<br>b) x^2-13x+42<br>c) x^2+x+42<br>d) x^2+x-15​
Sidana [21]

Answer:

B. x² - 13x + 42

Step-by-step explanation:

7 0
2 years ago
A bank in the Bay area is considering a training program for its staff. The probability that a new training program will increas
WITCHER [35]

Answer:

P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68

See explanation below.

Step-by-step explanation:

For this case we define first some notation:

A= A new training program will increase customer satisfaction ratings

B= The training program can be kept within the original budget allocation

And for these two events we have defined the following probabilities

P(A) = 0.8, P(B) = 0.2

We are assuming that the two events are independent so then we have the following propert:

P(A \cap B ) = P(A) * P(B)

And we want to find the probability that the cost of the training program is not kept within budget or the training program will not increase the customer ratings so then if we use symbols we want to find:

P(B' \cup A')

And using the De Morgan laws we know that:

(A \cap B)' = A' \cup B'

So then we can write the probability like this:

P(B' \cup A') = P((A \cap B)')

And using the complement rule we can do this:

P(B' \cup A') = P((A \cap B)')= 1-P(A \cap B)

Since A and B are independent we have:

P(A \cap B )=P(A)*P(B) =(0.8*0.4) =0.32

And then our final answer would be:

P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68

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Answer:

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Answer:

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Step-by-step explanation:

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