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bonufazy [111]
3 years ago
5

A 7-hour class will be divided into equal sessions of 7/5 (change it into a mixed number) hours. How many sessions will be neede

d
Mathematics
1 answer:
Vinvika [58]3 years ago
7 0
A 7 hour class is going to be divided into 7/5 hour long sessions. 7/5 when you divide (7÷5) = 1.4 To change 1.4 into a mixed number, we know that 0.4 is equal to four tenths or 4/10, thus the mixed number is 1 4/10. To find out how many sessions will be needed, we need to divide (7 ÷ 1 4/10) When this operation is done, your answer is 5. Therefore, 5 sessions will be needed.
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the expression 15 a + 12 C is the cost in dollars of a admission at an amusement park for a adults and see children find the tot
Blizzard [7]

Answer:

<em>$195</em>

Step-by-step explanation:

15a + 12c

5 adults and 10 children means a = 5 and c = 10

15a + 12c = 15(5) + 12(10) = 75 + 120 = 195

5 0
3 years ago
3x^2 + 64 = 2x^2/2 find the roots of the quadratic equation
Reil [10]

Answer:

4√2i , -4√2i.

Step-by-step explanation:

3x^2 + 64 = 2x^2/2

3x^2 + 64 = x^2

2x^2 + 64 = 0

2x^2 = -64

x^2 = -32

x = +/- √-32

x = +/- √16* -2

x = +/- 4√2 i.

8 0
4 years ago
This is an inequality andhave no idea
balandron [24]
Which numbers do you want? Also, you have to do the same thing on the other side if you do it on one. 
5 0
3 years ago
each course in college X is worth either two or three credits the members of the men’s swim team are taking a total of 47 course
omeli [17]

36 two credit courses and 11 three credit courses has been taken.

<u>SOLUTION: </u>

Given, each course in college X is worth either two or three credits. The members of the men’s swim team are taking a total of 47 courses that are worth a total of 105 credits .

We have to number of two credit courses and three credit courses are being taken .

Now, let the number of 2 credits courses be n, then number of 3 credits courses will be 47-n.

And, according to the given information,  Total credits = 105  

\begin{array}{l}{\rightarrow \text { Credits for two credit courses }+\text { credits from three credits courses }=105} \\\\ {\rightarrow 2 \times \text { number of two credit courses }+3 \times \text { number of three lcredit courses }=105} \\\\ {\rightarrow 2 \times n+3 \times(47-n)=105} \\\\ {\rightarrow 2 n+141-3 n=105} \\\\ {\rightarrow 3 n-2 n=141-105} \\\\ {\rightarrow n=36}\end{array}

So, two credits courses count is 36, the three credit courses count is 47-36 = 11

8 0
3 years ago
50 points to the first answer, will be checking the answers
melamori03 [73]

Answer:

.998543

9.92749

sqrt(101)

10 pi

Step-by-step explanation:

10 pi is approximately 10 * 3.14 = 31.4

.998543 is less than 1

9.927

sqrt(101) is a little more than sqrt(100)  which is 10

Smallest .998543

9.92749

sqrt(101)

10 pi

6 0
3 years ago
Read 2 more answers
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