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3 years ago

6

3x^2 + 64 = 2x^2/2 find the roots of the quadratic equation

1 answer:

Reil [10]3 years ago

8 0

Answer:

4√2i , -4√2i.

Step-by-step explanation:

3x^2 + 64 = 2x^2/2

3x^2 + 64 = x^2

2x^2 + 64 = 0

2x^2 = -64

x^2 = -32

x = +/- √-32

x = +/- √16* -2

x = +/- 4√2 i.

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