Answer:
In secondary succession, a previously occupied area is re-colonized following a disturbance that kills much or all of its community. A classic example of secondary succession occurs in oak and hickory forests cleared by wildfire. Wildfires will burn most vegetation and kill animals unable to flee the area.
<u>Answer:</u>
During the "magma convection currents", the plate tectonics are pulled apart from each other. This is because if the "magma convection currents" flow in opposite direction, the plates present floating on the molten magma also float apart, causing divergent plate boundaries.
The plate tectonics are responsible for the movement of continental plates. The molten magma present inside the earth acts as a vast ocean on which the plates move as sheets. So if currents flow away from each other they take the plates along with them too, forming great rift valleys.
The evolution of the peppered moth evolutionary instance of directional colour change in the moth population as a consequence of air pollution during the Industrial revolution .The frequency of dark-coloured moths increased at that time, an example of industrial mellaniam. Later, when pollution was reduced, the light-coloured form again predominated. Industrial melanism in the peppered moth was an early test of Charles Darwin natural selection in action, and remains as a classic example in the teaching of evolution.
Answer:
Glucose
Carbondioxide
Explanation:
1.Glucose is phosphorylated and broken down to pyruvate in the process called Glycolysis.
2.The pyruvate is decaboxylated ( loss of Carbon atoms) and enters Kreb cycle where 2 CO2 molecules are lost. 1 C02 from conversation of Citrate to alpha -ketoglutarate , and another 1 CO2 molecule loss from the conversion of Alpha keto glutarate to succinate; <u>for each turn of Kreb cycle. </u>
Therefore 4C02 are produced per one molecule of glucose in cellular respiration as the waste products
Answer:
The odd is zero.
Explanation:
Assuming the Huntington disease allele is represent by b. Nomal allele will be B which is the alternate form.
The genotype of the 25 years old woman will be Bb, since she heterozygote.
The genotype of the husband will be BB, since he's free from the trait.
Crossing both genotypes:
Bb x BB = BB, BB, Bb and Bb.
The genotypes of the offspring will be either BB or Bb. They either free from the trait or heterozygote.
<em>Hence, the odds that the couple will have a child with the disorder is 0. They can only produce heterozygotes or totally normal children.</em>
