Answer:
30 mL VOLUME OF 3.0 M HCl SHOULD BE USED BY THE STUDENT TO MAKE A 1.80 M IN 50 mL OF HCl.
Explanation:
M1 = 3.00 M
M2 = 1.80 M
V2 = 50 .0 mL = 50 /1000 L = 0.05 L
V1 = unknown
In solving this question, we know that number of moles of a solution is equal to the molar concentration multiplied by the volume. To compare two samples, we equate both number of moles and substitute for the required component.
So we use the equation:
M1 V1 = M2 V2
V1 = M2 V2 / M1
V2 = 1.80 * 0.05 / 3.0
V2 = 0.09 /3.0
V2 = 0.03 L or 30 mL
To prepare the sample of 1.80 M HCl in 50.0 mL from a 3.0 M HCl, 30 mL volume should be used.
Answer:
The volume of the gas will not change because the metal can is limiting it
Explanation:
Insead, Gay-Lussac's law tells us that the pressure will increase with the temprature unil the can eventually explodes, then allowing the volume to rapidly increase.
<span> The </span>formula mass<span> is calculated by adding up all the atomic </span>masses <span>for every atom in the </span>formula<span>. First, we need to know the atomic masses of the atoms involved.
H = 1.01 amu
S = 32.06 amu
Formula mass = 2 x </span>1.01 amu + 2 x 32.06 amu = 66.14 formula mass unit
Answer:
Graphs should be titled.
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Explanation:
