Question

At high temperatures, calcium carbonate (CaCO3) decomposes to form calcium oxide (CaO) and carbon dioxide (CO2) gas. The average mass of 1 calcium oxide molecule is 56.079 amu, and the average mass of 1 carbon dioxide molecule is 44.009 amu.
CaCO3 CaO + CO2
Which is the total mass of the 1 calcium carbonate molecule?
A. 12.070 amu
B. 44.009 amu
C. 56.079 amu
D. 100.088 amu

Answer 1

Answer:

Option D is correct

Explanation:

The individual mass of reactants in the reaction are

Calcium Oxide (CaO) =  $56.079$ amu

Carbon dioxide (CO2) $= 44.009$ amu

Since this reaction is a simple addition reaction in which no mass of the reactants is wasted. Also, no energy is released accompanied by conversion of mass into energy.

Hence, total mass of reactants would be equal to the mass of the product.

Thus, mass of calcium carbonate i.e CaCO3  is

$= 56.079 + 44.009$

$= 100.08$ amu

Hence, option D is correct