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agasfer [191]
3 years ago
8

this is due tonight and i need some help w/ it! how do mass and distance affect the strength of the force of gravity? -btw i nee

d a few sentences!
Chemistry
1 answer:
viktelen [127]3 years ago
8 0

Answer:

Mass is the amount of matter in an object. The distance is how far apart two places are from each other. They are related because the more mass the more gravitational force as then there is more pressure and then the gravitational force attracts the two objects closer. The more distance, the less the gravitational force as then the gravitational force will have more trouble attracting the two objects toward each other.

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Hich statement describes the process of fusion, but not the process of fission?
lesantik [10]

The answer is A. this process is only in the research phase

The process of fusion involves merging of atomic nuclei to form heavier nuclei resulting in the release of enormous amounts of energy. Fusion takes place when two low mass isotopes, typically isotopes of hydrogen, unite under conditions of extreme pressure and temperature. Scientists continue to work on controlling nuclear fusion in an effort to make a fusion reactor to produce electricity. However, progress is slow due to challenges with understanding how to control the reaction in a contained space.






4 0
3 years ago
A gas occupies a volume of 1.00 L at 25.0°C. What volume will the gas occupy at 1.00 x10^2 °C?
Leno4ka [110]

Answer : The volume of gas occupy at 1.00\times 10^2^oC is, 1.25 L

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=1.00L\\T_1=25.0^oC=(25.0+273)K=298K\\V_2=?\\T_2=1.00\times 10^2^oC=((1.00\times 10^2)+273)K=373K

Putting values in above equation, we get:

\frac{1.00L}{298K}=\frac{V_2}{373K}\\\\V_2=1.25L

Therefore, the volume of gas occupy at 1.00\times 10^2^oC is, 1.25 L

3 0
3 years ago
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adoni [48]

Answer:

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Explanation:

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3 years ago
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