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3 years ago

I need help with this question. Can someone help me?

Mathematics

1 answer:

Zina [86]3 years ago

4 0

Their coefficients are as follows (in order):

4
5
-4
-1

So if you were putting them in increasing order it would be
C, D, A, B

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Doug’s go-kart can go 50 m in 20s. What is its average speed?

Olegator [25]

Answer:

2.5m

Step-by-step explanation:

50m divided by 20 = 2.5m

4 0

2 years ago

Tickets for a minor league baseball game for an adult and two children cost a total of $21 the adult ticket is three dollars mor

oksian1 [2.3K]

Answer:the cost of one child's ticket is $6

the cost of one adult ticket is $9

Step-by-step explanation:

Let x represent the cost of one child's ticket

Let y represent the cost of one adult ticket.

Tickets for a minor league baseball game for an adult and two children cost a total of $21. This means that

2x + y = 21 - - - - - - - - - - 1

The adult ticket is three dollars more than a child's ticket. This means that

y = x + 3

Substituting y = x + 3 into equation 1, it becomes

2x + x + 3 = 21

3x + 3 = 21

3x = 21 - 3 = 18

x = 18/3 = 6

y = x + 3 = 6 + 3

y = 9

6 0

3 years ago

Use the figure to determine the intersection of planes EAB and EFG

vredina [299]

Answer:

Option (3). EF

Step-by-step explanation:

From the figure attached,

Plane defined by EAB can be represented by the face EABF of the square prism also.

Similarly, plane EFG can be represented by the face EFGH of the prism.

Now these sides EABF and EFGH are joining each other at the edge EF of the cuboid.

Therefore, intersection of the given planes is EF.

Option (3) will be the answer.

7 0

3 years ago

A particular isotope has a half-life of 74 days. If you start with 1 kilogram of this isotope, how much will remain after 150

shtirl [24]

$\bf \stackrel{150~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &150\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{150}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{75}{37}}\implies \boxed{A\approx 0.24536}$

$\bf \stackrel{300~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &300\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{300}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{150}{37}}\implies \boxed{A\approx 0.060202}$

6 0

2 years ago

Roman has a rope that is 25 1/2 feet long. he wants to cut it into 6 pieces that are equal in length. how long will each piece b

eduard

25.5*6=4.25 or 4.25
Your welcome

8 0

3 years ago