Question

My geometric sequence is 16,-3.2,0.64,-0.128..what is the 7th term

Answer 1

Answer:

Step-by-step explanation:

In a geometric sequence, the nth term is

T_n = ar^(n-1)

a = first term

r = common ratio which can be gotten by dividing second term by first term, third term by second term etc

Therefore

a = 16

r = -3.2 ÷ 16

r = -0.2

T_7 = ar^(7-1)

T_7 = ar^6

T_7 = 16[(-0.2)^6]

T_7 = 16(0.000064)

T_7 = 0.001024