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3 years ago

My geometric sequence is 16,-3.2,0.64,-0.128..what is the 7th term

Mathematics

1 answer:

USPshnik [31]3 years ago

6 0

Answer:

Step-by-step explanation:

In a geometric sequence, the nth term is

T_n = ar^(n-1)

a = first term

r = common ratio which can be gotten by dividing second term by first term, third term by second term etc

Therefore

a = 16

r = -3.2 ÷ 16

r = -0.2

T_7 = ar^(7-1)

T_7 = ar^6

T_7 = 16[(-0.2)^6]

T_7 = 16(0.000064)

T_7 = 0.001024

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A special type of password consists of 3 different letters of the alphabet, and the two different numbers, where each letter and

Phoenix [80]

Answer:

There can be 14,040,000 different passwords

Step-by-step explanation:

Number of permutations to order 3 letters and 2 numbers (total 5)

(AAANN, AANNA,AANAN,...)

= 5! / (3! 2!)

= 120 / (6*2)

= 10

For each permutation, the three distinct (English) letters can be arranged in

26!/(26-3)! = 26!/23! = 26*25*24 = 15600 ways

For each permutation, the two distinct digits can be arranged in

10!/(10-2)! = 10!/8! = 10*9 = 90 ways.

So the total number of distinct passwords is the product of all three permutations,

N = 10 * 15600 * 90 = 14,040,000

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3 years ago

Write the equation of a line in the given form.

Gnom [1K]

Answer:

$y = \frac{1}{4}x - 5$

Step-by-step explanation:

Slope intercept form: y = mx + b

Find slope:

m = (y₂ - y₁) / (x₂ - x₁)

= (-5 - (-4)) / (0 - 4)

= -1 / -4

= 1/4

Find y intercept using anyone of the given points and slope from above:

y = mx + b

$-5 = \frac{1}{4}(0) + b$

b = -5

Now use the above slope and y intercept to create equation of a line:

$y = \frac{1}{4}x - 5$

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3 years ago

A common blood test performed on pregnant women to screen for chromosome abnormalities in the fetus measures the human chorionic

goldfiish [28.3K]

Answer:

(a) The proportion of women who are tested, get a negative test result is 0.82.

(b) The proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

Step-by-step explanation:

The Bayes' theorem states that the conditional probability of an event E $_{i}$ , of the sample space S, given that another event A has already occurred is:

$P(E_{i}|A)=\frac{P(A|E_{i})P(E_{i})}{\sum\liits^{n}_{i=1}{P(A|E_{i})P(E_{i})}}$

The law of total probability states that, if events E₁, E₂, E₃... are parts of a sample space then for any event A,

$P(A)=\sum\limits^{n}_{i=1}{P(A|B_{i})P(B_{i})}$

Denote the events as follows:

X = fetus have a chromosome abnormality.

Y = the test is positive

The information provided is:

$P(X)=0.04\\P(Y|X)=0.90\\P(Y^{c}|X^{c})=0.85$

Using the above the probabilities compute the remaining values as follows:

$P(X^{c})=1-P(X)=1-0.04=0.96$

$P(Y^{c}|X)=1-P(Y|X)=1-0.90=0.10$

$P(Y|X^{c})=1-P(Y^{c}|X^{c})=1-0.85=0.15$

(a)

Compute the probability of women who are tested negative as follows:

Use the law of total probability:

$P(Y^{c})=P(Y^{c}|X)P(X)+P(Y^{c}|X^{c})P(X^{c})$

$=(0.10\times 0.04)+(0.85\times 0.96)\\=0.004+0.816\\=0.82$

Thus, the proportion of women who are tested, get a negative test result is 0.82.

(b)

Compute the value of P (X|Y) as follows:

Use the Bayes' theorem:

$P(X|Y)=\frac{P(Y|X)P(X)}{P(Y|X)P(X)+P(Y|X^{c})P(X^{c})}$

$=\frac{(0.90\times 0.04)}{(0.90\times 0.04)+(0.15\times 0.96)}$

$=0.20$

Thus, the proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

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3 years ago

Which linear inequality will not have a shared solution set with the graphed linear inequality?

Serggg [28]

C.............................

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3 years ago

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A family of 2 adults and 3 children went to a movie. The tickets cost $8 for adults and $5 for children. They also bought 3 soda

Nesterboy [21]

Answer:

Total for all the movie tickets:$31

Total for the sodas:$5.97

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3 years ago