My geometric sequence is 16,-3.2,0.64,-0.128..what is the 7th term
1 answer:
Answer:
Step-by-step explanation:
In a geometric sequence, the nth term is
T_n = ar^(n-1)
a = first term
r = common ratio which can be gotten by dividing second term by first term, third term by second term etc
Therefore
a = 16
r = -3.2 ÷ 16
r = -0.2
T_7 = ar^(7-1)
T_7 = ar^6
T_7 = 16[(-0.2)^6]
T_7 = 16(0.000064)
T_7 = 0.001024
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