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jolli1 [7]
4 years ago
8

I can't figure this out. help meeee

Mathematics
1 answer:
gogolik [260]4 years ago
7 0
3*5=15 15*8=120 Answer: 120m
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3 years ago
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In a different plan for area​ codes, the first digit could be any number from 4 through 8​, the second digit was either 3, 4, 5,
Snezhnost [94]

For the first digit, we have 5 options that are 4,5,6,7,8 . For the second digit, we have 4 options which are 3,4,5 or 6 and for the third digit, we have the options of all numbers except 2 or 5 that is 1,3,4,6,7,8,9,0 . SO we have 8 options for third digit . So to find the total number of options, we need to multiply all the possible options for each digit that is 5 times 4 times 8 = 160 . So the number of possible options are 160 .

7 0
4 years ago
X+6 /3 = 2+x-2/5
olasank [31]
We can treat this problem like you regularly subtract fractions. First find the common denominator, which is 15.

So:

5(x+6)/15 = 30/15 + 3(x-2)/15

(5x+6)/15 - (30/15) - (3x - 6)/15


As you already know the answer, I'm assuming you can do the rest.

Hope this helps!
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3 years ago
What must be the value of x so that lines a and b are<br> parallel lines cut by transversal f?
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