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galben [10]
3 years ago
15

Let a = x2 + 4. Use a to find the solutions for the following equation:

Mathematics
1 answer:
Zepler [3.9K]3 years ago
8 0

The solutions for x are -2, 0, 2

<em><u>Solution:</u></em>

Given that,

\text { Let } a = x^2 + 4

Given equation is:

(x^2 + 4)^2 + 32 = 12x^2 + 48

(x^2 + 4)^2 + 32 = 12(x^2 + 4)

\text { Subtsitute } a = x^2 + 4 \text{ in above equation }

a^2 + 32 = 12a\\\\a^2 -12a + 32 = 0

\text{ Let us factorize the above equation }\\\\\text{ Splitting the middle term -12a as -4a - 8a we get, }

a^2 -4a - 8a + 32 = 0

Taking "a" as common term from first two terms and taking "-8" as common from last two terms

a(a-4)-8(a - 4) = 0

\text{Taking (a - 4) as common term, }\\\\(a - 4)(a - 8) = 0

\text{Equating to zero we get, }\\\\(a - 4) = 0 \text{ or } (a - 8) = 0\\\\a = 4 \text{ or } a = 8

\text{Now substitute the value of a = 8 and a = 4 in: }\\\\a = x^2 + 4

\text{ For a = 8: }\\\\a = x^2 + 4\\\\8 = x^2 + 4\\\\x^2 = 4\\\\x = \pm2\\\\x = +2 \text{ or } -2

\text{For a = 4: }\\\\a = x^2 + 4\\\\4 = x^2 + 4\\\\x = 0

\text{Thus solutions of } x \text{ are: }\\\\x = 0 \text{ or } x = 2 \text{ or } x = -2

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Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
melamori03 [73]

Answer:

6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs AB=3, BC=4, and AC=5. The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base b and height h is given by A=\frac{1}{2}bh. Therefore, the area of this right triangle is:

A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}

The other triangle is a bit trickier. Triangle \triangle ADC is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by:

A=\sqrt{s(s-a)(s-b)(s-c)}, where a, b, and c are three sides of the triangle and s is the semi-perimeter (s=\frac{a+b+c}{2}).

The semi-perimeter, s, is:

s=\frac{5+5+4}{2}=\frac{14}{2}=7

Therefore, the area of the isosceles triangle is:

A=\sqrt{7(7-5)(7-5)(7-4)},\\A=\sqrt{7\cdot 2\cdot 2\cdot 3},\\A=\sqrt{84}, \\A=2\sqrt{21}\:\mathrm{cm^2}

Thus, the area of the quadrilateral is:

6\:\mathrm{cm^2}+2\sqrt{21}\:\mathrm{cm^2}=\boxed{6+2\sqrt{21}\:\mathrm{cm^2}}

4 0
3 years ago
34 is what percentage of 40
Zarrin [17]
Well 34 is 85% of 40
6 0
3 years ago
Which expressions are equivalent to √/32?<br> 4√8<br> 08<br> 2√8<br> 4√2<br> 16<br> 16√2
vaieri [72.5K]

Answer: 4√2

square root of a number is the factor that we can multiply by itself to get that number.

The square root symbol is also called as a RADICAL.

Perfect squares are the squares of the integers also called as square numbers.

to find the square root of non-perfect squared numbers we have to check the number with a near-perfect squared numbers

how to find square root of non perfect squared numbers:

If we can't figure out what factor multiplied by itself will result in the given number, we can make a factor tree.

Factor tree of 32 = 2*2*2*2*2

                            = (2*2) * (2*2) *2

                            = (4)2 *2

Therefore √/32 = √/2*2*2*2*2

                          = √/(4)2*2

                          = 4√/2

learn more about square roots here:

brainly.com/question/428672

brainly.com/question/3617398

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8 0
2 years ago
PLEASE HELP ASAP!!!
levacccp [35]

Answer:

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6 0
3 years ago
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