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Tanzania [10]
3 years ago
12

You are making homemade ice cream and can use either 200 g Ice Melt (CaCl2) or 200 g rock salt (NaCl) to lower the freezing poin

t of 7.00 kg of ice (assume the ice is pure water). Which salt would help you eat your ice cream faster (i.e. lower the freezing temperature of the ice)?
Chemistry
1 answer:
mash [69]3 years ago
5 0

Answer:

Calcium chloride (CaCl2) would help me eat my ice cream faster

Explanation:

Addition of salt to ice melts the lowers the freezing temperature of the ice thus melting the ice easily

Adding calcium chloride to my ice cream would help me eat it faster because the melting point of calcium chloride (772°C) is lower than that of sodium chloride (melting point is 801°C). Calcium chloride would melt my ice cream faster because of its lower melting point

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Answer : The theoretical yield of water formed from the reaction is 0.54 grams.

Solution : Given,

Mass of HCl = 1.1 g

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Molar mass of HCl = 36.5 g/mole

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Molar mass of H_2O = 18 g/mole

First we have to calculate the moles of HCl and NaOH.

\text{ Moles of }HCl=\frac{\text{ Mass of }HCl}{\text{ Molar mass of }HCl}=\frac{1.1g}{36.5g/mole}=0.030moles

\text{ Moles of }NaOH=\frac{\text{ Mass of }NaOH}{\text{ Molar mass of }NaOH}=\frac{2.1g}{40g/mole}=0.525moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

HCl+NaOH\rightarrow NaCl+H_2O

From the balanced reaction we conclude that

As, 1 mole of HCl react with 1 mole of NaOH

So, 0.030 mole of HCl react with 0.030 mole of NaOH

From this we conclude that, NaOH is an excess reagent because the given moles are greater than the required moles and HCl is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of H_2O

From the reaction, we conclude that

As, 1 mole of HCl react to give 1 mole of H_2O

So, 0.030 moles of HCl react to give 0.030 moles of H_2O

Now we have to calculate the mass of H_2O

\text{ Mass of }H_2O=\text{ Moles of }H_2O\times \text{ Molar mass of }H_2O

\text{ Mass of }H_2O=(0.030moles)\times (18g/mole)=0.54g

Therefore, the theoretical yield of water formed from the reaction is 0.54 grams.

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3 years ago
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