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Ivanshal [37]
3 years ago
15

Bob the chemist ran a TLC plate of his product, but the spot would not move off the baseline. The eluent he used consisted of a

30% polar / 70% non-polar solvent system. Which solvent system should he try next in order to get the compounds in his product mixture to move up the plate
Chemistry
1 answer:
olya-2409 [2.1K]3 years ago
7 0

Answer:

40 % polar / 60 % nonpolar system

Explanation:

According to the like-dissolves-like rule, remember that polar compounds dissolve in polar solvents and nonpolar compounds dissolve in nonpolar solvents.

Notice that the eluent used is only slightly polar and mainly nonpolar. Since the product didn't move at all, this means it didn't interact with the major nonpolar solvent and is expected to be polar.

That said, a more polar system should be used in order to make the product move off the baseline, such as 40 % polar and 60 % nonpolar solvent system.

In case the product still doesn't move, polarity of the eluent should be increased further.

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The lewis representation above depicts a reaction between hydrogen (blue) and a main-group element from group (red). in this rep
Fed [463]

The question is incomplete, the complete question is;

The Lewis representation above depicts a reaction between hydrogen (blue) and a main-group element from group______ (red).

In this representation, each Y atom needs ______ electron(s) to complete its octet, and gains these electrons by forming______ bond(s) with atoms of H .

There are ______ unshared electron pair(s) and _______bonding electron pair(s) in the product molecule.

The bonds in the product are _________ (Ionic or Covalent)

Answer:

1) 16

2) 2 electrons

3) 2 bonds

4) 2 unshared pairs of electrons

5) 2 bonding pairs of electrons

6) The bonds in the product are covalent

Explanation:

Group sixteen elements have six electrons on their outermost shell. These include two unshared pairs of electrons and two unpaired electrons. These two unpaired electrons can now be covalently bonded to two hydrogen atoms to give H2Y. The compound H2Y has two lone pairs and two bond pairs of electrons.

H2Y can be a general formula for all hydrides of group 16. They are all very similar in structure but gradually differ in physical and chemical properties according to the graduated variation observed down the group.

6 0
3 years ago
What is the molar mass of copper(II)nitrate
andriy [413]
<span>187.56 g/mol
That is the answer</span>
8 0
3 years ago
Read 2 more answers
What is the name of the isotope produced when Californium-251 emits an alpha particle?
Charra [1.4K]
<h3>Answer:</h3>

                 Curium-247 <em>i.e.</em> ²⁴⁷₉₆Cm

<h3>Explanation:</h3>

Alpha decay is given by following general equation,

                              ᵃₓA    →    ⁴₂He  +  ᵃ⁻⁴ₓ₋₂B

Where;

           A  =  Parent Isotope

           B  =  Daughter Isotope

           ᵃ  =  Mass Number

           ₓ  =  Atomic Number

Californium-251 is the parent isotope in our case and it has 98 protons (atomic number) and is given as,

                                                 ²⁵¹₉₈Cf

The alpha decay reaction of Californium-251 will be as,

                               ²⁵¹₉₈Cf     →     ⁴₂He  +  ²⁴⁷₉₆B

The symbol for B with atomic number 96 was found to be the atom of Curium (Cm) by inspecting periodic table. Hence, the final equation is as follow,

                               ²⁵¹₉₈Cf     →     ⁴₂He  +  ²⁴⁷₉₆Cm

3 0
3 years ago
The symbol of an element represents one atom of that element Ba=
Mama L [17]
Barium, it's an earthy alkaline metal it's atomic number is 56
4 0
3 years ago
When 91.5 g of isopropyl alcohol which has an empirical formula of C3H8O is burned in excess oxygen gas, how many grams of H2O a
Kobotan [32]

Answer:

109.7178g of H2O

Explanation:

First let us generate a balanced equation for the reaction. This is illustrated below:

2C3H8O + 9O2 —> 6CO2 + 8H2O

Next we will calculate the molar mass and masses of C3H8O and H20. This is illustrated below:

Molar Mass of C3H8O = (3x12.011) + (8x1.00794) + 15.9994 = 36.033 + 8.06352 + 15.9994 = 60.09592g/mol.

Mass of C3H8O from the balanced equation = 2 x 60.09592 = 120.19184g

Molar Mass of H2O = (2x1.00794) + 15.9994 = 2.01588 + 15.9994 = 18.01528g/mol

Mass of H2O from the balanced equation = 8 x 18.01528 = 144.12224g

From the equation,

120.19184g of C3H8O produced 144.12224g of H20.

Therefore, 91.5g of C3H8O will produce = (91.5 x 144.12224) /120.19184 = 109.7178g of H2O

7 0
3 years ago
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