Answer:
Step-by-step explanation:
<h3>Part A</h3>
- a = 100 will convert the number on the numerator to whole number
- b = 10 will convert the number on the denominator to whole number
But we need a = b in order not to change the value of the fraction, therefore we choose
<h3>Part B</h3>
Multiplying both numerator and denominator by 100 will make the fraction:
- 35.86*100/2.2*100 =
- 3586/220 =
- 16 66/220 =
- 16 3/10
- 16.3
Fermat's little theorem states that

≡a mod p
If we divide both sides by a, then

≡1 mod p
=>

≡1 mod 17

≡1 mod 17
Rewrite

mod 17 as

mod 17
and apply Fermat's little theorem

mod 17
=>

mod 17
So we conclude that

≡1 mod 17
Answer:
20 x 1 / 18= 1.11
Step-by-step explanation:
Answer: $20
Step-by-step explanation:
If she already has 9, and she needs 49, take that extra 9 off 49 and then she needs 40 more and she gets 2 for a dollar, she'll need to spend $20 to get 40 headbands. Can I please get Brainliest?