Which rule represents the translation form the pre image ABC to the image A’B’C’
1 answer:
The rest of the question is the attached figure.
As shown in the graph
The coordinates of the image ABC are:
A(-3,4) , B(-4,1) and C(-2,1)
And the coordinates of A'B'C' are:
A'(4,-2) , B'(3,-5) and C'(5,-5)
So,
A' - A = (4,-2) - (-3,4) = (7,-6) →(1)
B' - B = (3,-5) - (-4,1) = (7,-6) →(2)
C' - C = (5,-5) - (-2,1) = (7,-6) →(3)
So, from (1), (2) and (3)
The <span>rule represents the translation form the pre image ABC to the image A’B’C’ is ⇒⇒⇒ </span><span>(x, y) → (x + 7, y – 6)</span>
As shown in the graph
The coordinates of the image ABC are:
A(-3,4) , B(-4,1) and C(-2,1)
And the coordinates of A'B'C' are:
A'(4,-2) , B'(3,-5) and C'(5,-5)
So,
A' - A = (4,-2) - (-3,4) = (7,-6) →(1)
B' - B = (3,-5) - (-4,1) = (7,-6) →(2)
C' - C = (5,-5) - (-2,1) = (7,-6) →(3)
So, from (1), (2) and (3)
The <span>rule represents the translation form the pre image ABC to the image A’B’C’ is ⇒⇒⇒ </span><span>(x, y) → (x + 7, y – 6)</span>
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