Answer:
On average, cars enter the highway during the first half hour of rush hour at a rate 97 per minute.
Step-by-step explanation:
Given that, the rate R(t) at which cars enter the highway is given the formula
The average rate of car enter the highway during first half hour of rush hour is the average value of R(t) from t=0 to t=30.
![=[100(t-0.0001\frac{t^3}{3})]_0^{30}](https://tex.z-dn.net/?f=%3D%5B100%28t-0.0001%5Cfrac%7Bt%5E3%7D%7B3%7D%29%5D_0%5E%7B30%7D)
![=100[(30-0.0001\frac{30^3}{3})-(0-0.0001\frac{0^3}{3})]](https://tex.z-dn.net/?f=%3D100%5B%2830-0.0001%5Cfrac%7B30%5E3%7D%7B3%7D%29-%280-0.0001%5Cfrac%7B0%5E3%7D%7B3%7D%29%5D)
=2901
The average rate of car is 
=97
On average, cars enter the highway during the first half hour of rush hour at a rate 97 per minute.
Answer:
awwww shoot I really don't know know but I can maybe at least try to help you out and get some help to help you. I really don't make sense awww me
Answer:
m∠U = 103° and m∠TRS = 6°
Step-by-step explanation:
In the given circle O,
Since, RS║VU, and VR is a transverse,
Therefor, m∠V + m∠R = 180° [Consecutive interior angles]
m∠R + 103° = 180° [m∠R = 103° given]
m∠R = 180° - 103°
m∠R = 77°
Since m∠R = m∠VRT + m∠TRS
77° = 71° + m∠TRS
m∠TRS = 77° - 71° = 6°
Quadrilateral RTUV is a cyclic quadrilateral.
Therefore, m∠U + m∠R = 180°
m∠U + 77° = 180°
m∠U = 180° - 77° = 103°
Answer:
1.0712
Step-by-step explanation:
if you increase by 4%, it means you will have a new total of 104%. In decimals it is 1.04 (divide your percentage by 100) after that you do the same with the 3% increase. you'll have a new total of 103%. In decimals 1.03. If you want to know what single multiplier you can use, you need to multiply the both decimals. So you get 1.04 x 1.03 = 1.0712
hope this will help you, have a nice day!
