Given that f(x)=3x+1 and g(x)=4x+2/4, solve for g(f(0))

1 answer:

7 0

$f(x)=3x+1\\\\g(x)=\dfrac{4x+2}{4}\\\\f(0)=3\cdot0+1=0+1=1\\\\g(f(0))=g(1)=\dfrac{4\cdot1+2}{4}=\dfrac{4+2}{4}=\dfrac{6}{4}=\dfrac{6:2}{4:2}=\dfrac{3}{2}=1.5$

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