Sin2(x) +cos(x)=1
from the relation: (sin2(x) +cos2(x) =1 )
so , sin2(x)=1-cos2(x)
by subs. in the main eqn.
1-cos2(x) + cos(x) =1
by simplify the eqn.
cos(x) -cos2(x)=0
take cos(x) as a common factor
cos(x)* (1-cos(x))=0
then cos(x)=0 && cos(x)=1
cos(x)=0 if x= pi/2
& cos(x) = 1 if x = 0 , 2*pi
so the solution is x= {0,pi/2 , 2*pi}
yo sup??
mid point of circle=centre of circle
let centre be O(3,2)
and the point be P(-4,8) and the other point be Q(x,y)
by mid point formula
-4+x/2=3 and 8+y/2=2
x=10 and y=-4
therefore coordinates of the other point are (10,-4)
Hope this helps.
Answer:
8
Step-by-step explanation:
140-122=18
18-10=8
Answer:
A.) -3
Step-by-step explanation:
-3 is less than -2 therefore, it fits the answer.
The correct answer of the given question above would be option D. The thing that must happen for historians to consider a particular time in a civilization as a classical period is that, the civilization must make extraordinary achievements in areas such as art and science.
