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Kay [80]
3 years ago
14

Which is the final event that occurs when a star is forming?

Biology
1 answer:
DiKsa [7]3 years ago
6 0

Answer:

D. Nuclear fusion begins under high pressure.

Explanation:

A star is a giant astronomical or celestial object that is comprised of a luminous sphere of plasma, binded together by its own gravitational force.

Some of the examples of stars are;

  • Canopus.
  • Sun (closest to the Earth)
  • Betelgeuse.
  • Antares.
  • Vega.

Stars are typically made up of two (2) main hot gas, Hydrogen (H) and Helium (He). The chronological order in which the formation of a star occur are;

1. Gravity pulls gas and dust together to form dense cores.

2. A protostar forms as mass increases.

3. Nuclear fusion begins under high pressure.

Hence, the final event that occurs when a star is forming is that nuclear fusion begins under high pressure.

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Protects cells made of cellulose allows materials in and out
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The green machines within a plant are the blank.<br>Lysosomes chloroplasts mitochondria
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Synapomorphies are used in determining relationships among animal groups. Synapomorphies are:
maxonik [38]

Answer: (B) shared, derived traits.

Explanation:

In phylogenetic systematics, which presents itself with a character that eventually changes in descent, and presents itself with variations, which subsequently convert in the next generations. In this way, the character presence is not unique to the ancestor, but also in all heirs, however with a possible variation. This new variation or new character state is recognized as a derived condition, arose from the change in the state of the ancestral character. A derived condition has the potential to serve as a determinant for defining a new group is called apomorphy. An apomorphy can be unique to a group and is called a case of autapomorphy, or when it is shared by two or more groups it is called synapomorphy.

4 0
3 years ago
101. Du
n200080 [17]

Answer:

0.972 J/g^{\circ}C

Explanation:

When the sample of hot metal is placed inside the water, the metal gives off heat to the water: the temperature of the metal decreases while the temperature of the water increases, until the two reach an equilibrium temperature.

The heat given off by the metal is equal (in magnitude) to the heat absorbed by the water, so we can write:

Q_m=Q_w\\m_m C_m (T_m-T_e) = m_w C_w (T_e-T_w)

where:

m_m=26.0 g is the mass of the metal

C_m is the specific heat of the metal

T_m=82.25^{\circ}C is the initial temperature of the metal

T_e=28.34^{\circ}C is the equilibrium temperature

m_w=75.0 g is the mass of the water

C_w=4.186 J/g^{\circ}C is the specific heat of water

T_w=24.00^{\circ}C is the initial temperature of the water

And solving for C_m, we find the specific heat of the metal:

C_m=\frac{m_w C_w (T_e-T_w)}{m_m(T_m-T_e)}=\frac{(75.0)(4.186)(28.34-24.00)}{(26.0)(82.25-28.34)}=0.972 J/g^{\circ}C

3 0
3 years ago
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