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3 years ago

Can someone please help me.

Mathematics

2 answers:

Colt1911 [192]3 years ago

8 0

Answer:

10 $\sqrt{2}$

Step-by-step explanation:

Natasha2012 [34]3 years ago

3 0

Answer:10√2

Step-by-step explanation:

∆ABC is a right angle triangle

Angle A + Angle B + angle C = 180

There angel B = 180-135= 45

Angle A = Angle B

Therefore AC= BC=10

By Pythagoras ppt AB^2=10^2 +10^2

=100+100

=√200

=10√2

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Given g(x) = f(x) + k. Identify a value of k that transforms finto g. Round your answer to the nearest integer. g 2 X - 14 -2 O

Keith_Richards [23]

Answer:

k = -5

Step-by-step explanation:

We can see the lines are parallel

The function f(x) has y-intercept of 2 at point (2, 0) and the function g(x) has y-intercept of -3 at point of (-3, 0)

If f(x) = mx + 2, then g(x) = mx - 3

The value of k is the difference of y-intercepts as slopes are same due to lines being parallel:

g(x) = f(x) + k
k = g(x) - f(x)
k = (mx - 3) - (mx + 2)
k = -3 - 2
k = -5

So the answer is k = -5

4 0

2 years ago

Use a flowchart to prove if the triangles in each pair are congruent. NO LINKS!!!!

valentinak56 [21]

9514 1404 393

Answer:

see attached

Step-by-step explanation:

It isn't clear what is supposed to go in the various blanks. We have elected to identify the corresponding congruent parts, and name the congruent triangles. The postulate supporting the conclusion is also shown.

In most cases, corresponding parts are marked congruent. The exception is the vertical angles in figure 22.

7 0

3 years ago

Read 2 more answers

A wire is attached at the top of a 500 ft vertical antenna and is staked in the ground 1200 ft from the base of the antenna. how

Lady_Fox [76]

A^2 + b^2 = c^2
(500)^2 + (1200)^2 = c^2
1,690,000 = c^2
take the square root of 1,690,000
Answer is 1,300 feet

8 0

3 years ago

Y=-×+1 and y=2×+4 how many solutions when graphed

dedylja [7]

Answer:

One solution (-1,2)

Step-by-step explanation:

Since these two linear equations have different slopes, different y-intercepts, and are indeed linear, these equations will only have one crossing when graphed, and hence one solution.

To find that solution, we can simply set the equations equal to each other.

y = -x + 1

y = 2x + 4

-x + 1 = 2x + 4

-3 = 3x

-1 = x

Now plug that value back into one of the equations:

y = -x + 1

y = -(-1) + 1

y = 2

So now you know the crossing for these two equations occurs at (-1,2).

Cheers.

3 0

3 years ago

!!!!!!!!!!!!!!!!!!!!

Andru [333]

Answer:

$f^{-1}(x)=4x+20$

Step-by-step explanation:

Given

$f(x)=\frac{x}{4}-5\\ \\y=\frac{x}{4}-5$

Swap x and y and solve for y

$y=\frac{x}{4}-5\\ \\x=\frac{y}{4}-5\\ \\x+5=\frac{y}{4}\\ \\4(x+5)=y\\\\y=4x+20$

Final answer

$f^{-1}(x)=4x+20$

Keep in mind that we need to swap the variables because a function and its inverse are symmetrical about the line y=x. See the graph below.

3 0

2 years ago