<h2>
<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>:</u></h2><h3>
<u>D</u><u> </u><u>i</u><u>s</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u></h3>
<em><u>Y</u></em><em><u>e</u></em><em><u>s</u></em><em><u>.</u></em><em><u> </u></em><em><u>balancing an unknown mass against a known mass.</u></em>
<h2>
<em><u>E</u></em><em><u>x</u></em><em><u>p</u></em><em><u>l</u></em><em><u>a</u></em><em><u>n</u></em><em><u>a</u></em><em><u>t</u></em><em><u>i</u></em><em><u>o</u></em><em><u>n</u></em><em><u>:</u></em></h2>
Hope it helps
#CARRYONLEARNING
Answer:
x=−3
Step-by-step explanation:
Move all terms that don't contain
x to the right side and solve.
hope this helps !
Step-by-step explanation:
what is to be done ? just that addition ?
first, let's all bring to pure fractions.
7 2/3 = (7×3 + 2)/3 = 23/3
2 1/5 = (2×5 + 1)/5 = 11/5
then let's bring all to a common denominator (bottom part of the fraction).
for this, we need to find the first (or any) common multiple of the 2 denominators (here 3 and 5).
if you have no other idea, just multiply them with each other (in our case here this is also the smallest common multiple) : 3×5 = 15.
so, we bring both fractions into the form of .../15. then it is easy to add them.
23/3 = x/15
x = 23/3 × 15 = 23×15/3 = 23×5 = 115
=>
23/3 = 115/15
11/5 = x/15
x = 11/5 × 15 = 11×15/5 = 11×3 = 33
=>
11/5 = 33/15
now the addition :
115/15 + 33/15 = 148/15 or 9 13/15
this is the result, as it cannot be further simplified.
The blue one and the small purple one are similar because they have the same angles.
Answer:
4 less kilgrams than previous weight
Step-by-step explanation:
