Question 3

In Hooke’s law, what does the x represent?

Mice21 [21]

Answer: C

X = Displacement of the spring

Hooke's law: It states that the applied force F is proportional to the displacement of spring .

F ∝ x

Where, x = displacement of spring in meters

F = force, measured in Newtons

In another words The force F is equal to the constant K times the disparagement.

F = k.x

Where k is constant and it depends on elastic material.

Spring has restorative force.

If the spring moves in opposite direction then,

F = - k.x

A negative sign indicates that the spring resists and force is to the left. The compression of the spring is greater than the restoring force.

Example: A mass 'm' stretches a spring at a displacement x.

6 0

4 years ago

Por que no céu sem nuvens a lua nova não é visivel e a lua cheia aparece em grande destaque?

weeeeeb [17]

Porque la matematica es imposible

4 0

3 years ago

What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q3 = 55.0 nC placed between q1

notka56 [123]

Complete Question

Part of the question is shown on the first uploaded image

The rest of the question

What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q3 = 55.0 nC placed between q1 and q2 at x3 = -1.220 m ? Your answer may be positive or negative, depending on the direction of the force. Express your answer numerically in newtons to three significant figures.

Answer:

The net force exerted on the third charge is $F_{net}= 3.22*10^{-5} \ J$

Explanation:

From the question we are told that

The third charge is $q_3 = 55 nC = 55 *10^{-9} C$

The position of the third charge is $x = -1.220 \ m$

The first charge is $q_1 = -16 nC = -16 *10^{-9} \ C$

The position of the first charge is $x_1 = -1.650m$

The second charge is $q_2 = 32 nC = 32 *10^{-9} C$

The position of the second charge is $x_2 = 0 \ m$

The distance between the first and the third charge is

$d_{1-3} = -1.650 -(-1.220)$

$d_{1-3} = -0.43 \ m$

The force exerted on the third charge by the first is

$F_{1-3} = \frac{k q_1 q_3}{d_{1-3}^2}$

Where k is the coulomb's constant with a value $9*10^{9} \ kg\cdot m^3\cdot s^{-4}\cdot A^2.$

substituting values

$F_{1-3} = \frac{9*10^{9}* 16 *10^{-9} * (55*10^{-9})}{(-0.43)^2}$

$F_{1-3} = 4.28 *10^{-5} \ N$

The distance between the second and the third charge is

$d_{2-3} = 0- (-1.22)$

$d_{2-3} =1.220 \ m$

The force exerted on the third charge by the first is mathematically evaluated as

$F_{2-3} = \frac{k q_2 q_3}{d_{2-3}^2}$

substituting values

$F_{2-3} = \frac{9*10^{9} * (32*10^{-9}) *(55*10^{-9})}{(1.220)^2}$

$F_{2-3} = 1.06*10^{-5} N$

The net force is

$F_{net} = F_{1-3} -F_{2-3}$

substituting values

$F_{net} = 4.28 *10^{-5} - 1.06*10^{-5}$

$F_{net}= 3.22*10^{-5} \ J$

6 0

3 years ago

How much work was done on a 45 kg weight when lifted 1.4 meters in the air?

BabaBlast [244]

Explanation:

w = f x d

45 x 1.4 = 630j

to get newton's do 45 x gravitation field strength

8 0

3 years ago

Que formas de energía utilizas habitualmente?

Luda [366]

Esta energía puede ser convertida en otras, como calor para calentar agua o edificios, invernaderos etc. o electricidad. Podemos convertir la energía solar en eléctrica de dos formas: Fotovoltáica (PV): La radiación solar se convierte directamente en electricidad

hope this help mark brainliest plz

5 0

3 years ago