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Dahasolnce [82]
3 years ago
8

A physics student shoves a 0.50-kg block from the bottom of a frictionless 30.0° inclined plane. The student performs 4.0 j of w

ork and the block slides a distance s along the incline before it stops. Determine the value of s.
Physics
1 answer:
Musya8 [376]3 years ago
5 0

Answer:1.63 m

Explanation:

Given

mass of block m=0.5 kg

inclination \theta =30^{\circ}

Amount of work done W=4 J

block slides a distance s along the Plane

Work done =change in Potential Energy

Increase in height of block is s\sin \theta

Change in Potential Energy =mg(\sin \theta -0)

\Delta P.E.=0.5\times 9.8\times s\sin 30

4=0.5\times 9.8\times s\sin 30

s=\frac{4}{2.45}      

s=1.63 m

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14. A rocket is shot up into the air and then comes back down and hits the ground 9.2 second later.
sineoko [7]

Answer:

105.8 m

46 m/s

Explanation:

From the time the rocket is launched to the time it reaches its maximum height:

v = 0 m/s

a = -10 m/s²

t = 9.2 s / 2 = 4.6 s

Find: Δy and v₀

Δy = vt − ½ at²

Δy = (0 m/s) (4.6 s) − ½ (-10 m/s²) (4.6 s)²

Δy = 105.8 m

v = at + v₀

0 m/s = (-10 m/s²) (4.6 s) + v₀

v₀ = 46 m/s

3 0
3 years ago
A pitcher throws a baseball that reaches the catcher in 0.75 s. The ball curves because it is spinning at an average angular vel
7nadin3 [17]

The change in angular displacement as a function of time is the definition given for angular velocity, this is mathematically described as

\omega = \frac{\theta}{t}

Here,

\theta = Angular displacement

t = time

The angular velocity is given as

\omega = 230rev/min

PART A) The angular velocity in SI Units will be,

\omega = 230rev/min (\frac{1min}{60s})(\frac{2\pi rad}{1rev})

\omega = \frac{23}{3}\pi rad/s \approx 24.08rad/s

PART B) From our first equation we can rearrange to find the angular displacement then

\theta = \omega t

Replacing,

\theta = (24.08)(0.75)

\theta = 18.06 rad

4 0
3 years ago
PLS HELP ME OUT!!
MaRussiya [10]
In order to solve this problem, we must first find out the value of each line on the number line. However, we can make this problem more simple by ignoring every interval except for the ones between 0 and 6. There are three total intervals in between 0 and 6 (including 6 and excluding 0). Therefore, we can do 6/2, and get an interval value of 2. This means that each line adds a value of 2. Since the car is only one line past zero, we only have to add one value of 2. Since 0 + 2 = 2, our final answer is C. 2.

Hope this helps!
4 0
3 years ago
Read 2 more answers
What happens when the voltage increases and the resistance stays the same in a electrical circuit?
Orlov [11]

Answer:

The current in the circuit increases

Explanation:

The ohm's law states that the potential across a circuit is proportional to the current in the circuit.

                                             V ∝ I

Where 'V' is the potential difference across the circuit and 'I' is the current in the circuit.

The proportionality constant present in the equation is the resistance of the circuit. Hence, the equation becomes

                                             V = IR

According to the equation, when V is directly proportional to 'I' where 'R' remains as constant, then the change in 'V is brings change in 'I' to make the equation valid.

So, when there is an increase in the voltage, the current on the circuit increases.

4 0
3 years ago
An archer defending a castle is on an 15.5 m high wall. He shoots an arrow straight down at 22.8 m/s. How much time does it take
kodGreya [7K]

Answer:

  about 602 milliseconds

Explanation:

The motion can be approximated by the equation ...

  y = -4.9t^2 -22.8t +15.5

where t is the time since the arrow was released, and y is the distance above the ground.

When y=0, the arrow has hit the ground.

Using the quadratic formula, we find ...

  t = (-(-22.8) ± √((-22.8)^2 -4(-4.9)(15.5)))/(2(-4.9))

  = (22.8 ± √823.64)/(-9.8)

The positive solution is ...

  t ≈ 0.60195193

It takes about 602 milliseconds for the arrow to reach the ground.

8 0
3 years ago
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