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4 years ago

Help please I really need help in this one

Physics

1 answer:

irina [24]4 years ago

3 0

It is 6 yrs
.
away from the sun

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Draw a well labelled diagram of a refrigerator

motikmotik

Answer:

Explanation:mark me brainliest

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3 years ago

1. A huge spool of wire, 10,000 meters long, weighs 81.34 N. You cut off a meter or so and tie it between two posts, 0.660 m apa

WARRIOR [948]

Answer:

The beat frequency is 6.378 Hz.

Explanation:

Given that,

Length of wire = 10000 m

Weight = 81.34 N

Distance = 0.660 m

Tension = 52 N

Frequency = 196 Hz

We need to calculate the mass of the wire

Using formula of weight

$W= mg$

$m = \dfrac{W}{g}$

Put the value into the formula

$m=\dfrac{81.34}{9.8}$

$m=8.3\ kg$

The mass per unit length of the wire

$m_{l}=\dfrac{m}{l}$

Put the value into the formula

$m_{l}=\dfrac{8.3}{10000}$

$m_{l}=8.3\times10^{-4}\ kg/m$

We need to calculate the frequency in the wire

Using formula of frequency

$f_{w}=\dfrac{1}{2l}\sqrt{\dfrac{T}{m_{l}}}$

Put the value into the formula

$f_{w}=\dfrac{1}{2\times0.660 }\sqrt{\dfrac{52}{8.3\times10^{-4}}}$

$f_{w}=189.62\ Hz$

We need to calculate the beat frequency

Using formula of beat frequency

$f_{b}=f_{in}-f_{w}$

Put the value into the formula

$f_{b}=196-189.622$

$f_{b}=6.378\ Hz$

Hence, The beat frequency is 6.378 Hz.

5 0

3 years ago

What component of fitness should you work on every time you exercise?

Pepsi [2]

Answer:

1.body composition, (2) flexibility, (3) muscular strength, (4) muscular endurance, and (5) cardio respiratory endurance.

Explanation:

8 0

3 years ago

Read 2 more answers

If you hike up Eagle Mountain to its peak (highest elevation), what side would be easiest to climb up: East or West? How do you

mihalych1998 [28]

because I googled it and are you going there or something

6 0

4 years ago

Two cars are traveling around identical circular racetracks. Car A travels at a constant speed of 20 m/s. Car B starts at rest a

Tomtit [17]

Answer:

b. it has the same centripetal acceleration as car A.

Explanation:

According to the question, the data provided is as follows

Constant speed of car A = 20 m/s

Constant tangential acceleration until its speed is 40 m/s

Based on the above information, the true statement is the same centripetal acceleration as car A because

As we know that

Centripetal acceleration is

$= \frac{V^2}{r}$

where,

$V^2$ = velocity

r = radius of the path

Now if both car A and car B moving in the same or identical circular path having the same velocity so in this case there is the same centripetal acceleration for that particular time

hence, the second option is correct

3 0

4 years ago