The first part of the question is:
Two point charges are placed on the x axis. (Attached file)The first charge, q1 = 8.00 nC , is placed a distance 16.0 m from the origin along the positive x axis; the second charge, q2 = 6.00 nC , is placed a distance 9.00 m from the origin along the negative x axis.
Answer:
q3 = +0.3nc
Explanation:
Due to the vector symbols in the solution, I've decided to attach the explanation to this answer.
Answer:
a) 1504.8 J
b) 991.76 J
c) 0J
d) 0J
Explanation:
(a) The work done by the force P on the box is given by the following formula:

P: applied force = 171N
x: distance in which the for P is applied = 8.80m
you replace the values of P and x and obtain:

(b) The work don by the friction force is:

μ = coefficient of kinetic friction = 0.250
M: mass of the box = 46.0kg
g: gravitational constant = 9.8 m/s^2

(c) The Normal force is

but this force does not do work on the box because the direction is perpendicular to the direction of the force P.

(d) the same as before:

Working...
length of wire L = 1.5 m
current I = 7 A
potential difference V = 68 Volt
According to Ohm's Law
V = IR
R = V/I
R = 68/7
R = 9.7 Ω
Answer:
They weight the same, they're both 1 kilogram