Answer:
lowest frequency = 535.93 Hz
distance between adjacent anti nodes is 4.25 cm
Explanation:
given data
length L = 32 cm = 0.32 m
to find out
frequency and distance between adjacent anti nodes
solution
we consider here speed of sound through air at room temperature 20 degree is approximately v = 343 m/s
so
lowest frequency will be = 
..............1
put here value in equation 1
lowest frequency will be = 
lowest frequency = 535.93 Hz
and
we have given highest frequency f = 4000Hz
so
wavelength = 
..............2
put here value
wavelength = 
wavelength = 0.08575 m
so distance = 
..............3
distance = 
distance = 0.0425 m
so distance between adjacent anti nodes is 4.25 cm
Answer:
This is the complete answer and step by step explanation.
Given:
a = 3m/s
m = 85 kg
Unknown:
The Kinetic energy of the man jogging
Formula and solution:
KE = 1/2 mv²
KE = 1/2(85 kg)(3 m/s)²
KE = (42.5 kg)(9 m²/s²)
Final Answer:
KE = 382.5 kg.m²/s² or simplify as 382.5 J is the kinetic energy of man jogging
Box-1 . . . D
Box-2 . . . B
Box-3 . . . A
Box-4 . . . C
Answer:
Explanation:
Given data:
Mass of the man, 
Total mechanical energy, 
Height, 
Suppose there is no external force acting on the man. In this situation, the total mechanical energy (kinetic + potential) will remain steady.
Let the speed of the man at 2.6 m be <em>v</em>.
Thus,
