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jarptica [38.1K]
3 years ago
8

What is the area of a semi-circle with a diameter of 6cm?

Mathematics
2 answers:
Readme [11.4K]3 years ago
6 0

Answer:

Area of the semicircle = 14.13cm^2

Step-by-step explanation:

Area of a circle=\pi r^2

Area of a semicircle= \pi r^2/2

For:

  Diameter=6 cm

 Radius= 6/2=3 cm

As, \pi =\frac{22}{7}=3.14

Area of the semicircle:

                  =(3.14*3*3)/2

          =(3.14*9)/2\\\\=28.26/2\\\\=14.13cm^2

Area of the semicircle = 14.13cm^2

ANEK [815]3 years ago
3 0

Formula for the area of a circle: A = pi * r^2

A semi-circle is half of a circle. So, we will need to divide the area of the total circle by 2 to find the area of a semi-circle.

r = d / 2

r = 6 / 2 = 3

A = pi * 9

A = 9pi

Semi-circle:

A = 9pi / 2

A = 4.5 pi cm^2 or 14.14 cm^2

Hope this helps!! :)

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Aleksandr-060686 [28]

Answer:

70

Step-by-step explanation:

Since these two are same side interior angles, their measures must be supplementary. This means that they must add up to 180 degrees. Therefore:

45+2x-5=180

2x+40=180

2x=140

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5 0
3 years ago
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xxTIMURxx [149]
If solving for y: 

→ 2x + y = 8
→ Take away 2x from both sides
→ y = 8 - 2x

If solving for x:

→ 2x + y = 8
→ Take away y from both sides
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8 0
3 years ago
Between which to whole numbers does the square root of 119 lie?
Stella [2.4K]

Answer:

10 and 11

Step-by-step explanation:

1^2, 2^2, 3^2, 4^2, 5^2, 6^2, 7^2, 8^2, 9^2, 10^2, 11^2\\1, 4, 9, 16, 25, 36,49,64,81,100,121

The \sqrt{119} lies between whole number 10 and 11 since it lies between 100-121 which square rooted, is 10 and 11.

4 0
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This is important<br> to meee help
Rina8888 [55]

Answer:

I'll help you! Answer is <u>3/2</u>. It's Friday so most people aren't on Brainly doing homework lol

Step-by-step explanation:

The heaviest bag (far right) weighs 4.75 lbs, whereas the lightest bag (far left) weighs 3.25 lbs. As mixed numbers, these would be 4\frac{3}{4}  and 3\frac{1}{4}. To find how much heavier the 4.75 lb bag is, you must subtract the 2 numbers.

<h3>Step 1. Convert each to a complex fraction</h3>

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3\frac{1}{4}  =  \frac{13}{4}

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<h3>Step 2. Subtract fractions like normal </h3>

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