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Olenka [21]
3 years ago
9

What is the answer too 3-3*6 2=?

Mathematics
1 answer:
liq [111]3 years ago
7 0
3-(3x62)=
3x62=186-3=183
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Qual o resultado de <br> 3842-269
marissa [1.9K]

Answer:

es 3573

Step-by-step explanation:

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2 years ago
Help plz im so stuck
kari74 [83]

Answer: yes

Step-by-step explanation:

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3 years ago
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Find the general solution to 3y′′+12y=0. Give your answer as y=... . In your answer, use c1 and c2 to denote arbitrary constants
lozanna [386]

Answer:

y(x)=c_1e^{2ix}+c_2e^{-2ix}

Step-by-step explanation:

You have the following differential equation:

3y''+12y=0     (1)

In order to find the solution to the equation, you can use the method of the characteristic polynomial.

The characteristic polynomial of the given differential equation is:

3m^2+12=0\\\\m^2=-\frac{12}{3}=-4\\\\m_{1,2}=\pm2\sqrt{-1}=\pm2i

The solution of the differential equation is:

y(x)=c_1e^{m_1x}+c_2e^{m_2x}   (2)

where m1 and m2 are the roots of the characteristic polynomial.

You replace the values obtained for m1 and m2 in the equation (2). Then, the solution to the differential equation is:

y(x)=c_1e^{2ix}+c_2e^{-2ix}

4 0
3 years ago
A survey found that​ women's heights are normally distributed with mean 63.2 in. and standard deviation 2.4 in. The survey also
Effectus [21]

Answer: 99.51%

Step-by-step explanation:

Given : A survey found that​ women's heights are normally distributed.

Population mean : \mu =63.2  \text{ inches}

Standard deviation: \sigma= 2.4\text{ inches}

Minimum height = 4ft. 9 in.=4\times12+9\text{ in.}=57\text{ in.}

Maximum height = 6ft. 2 in.=6\times12+2\text{ in.}=74\text{ in.}

Let x be the random variable that represent the women's height.

z-score : z=\dfrac{x-\mu}{\sigma}

For x=57, we have

z=\dfrac{57-63.2}{2.4}\approx-2.58

For x=74, we have

z=\dfrac{74-63.2}{2.4}\approx4.5

Now, by using the standard normal distribution table, we have

The probability of women meeting the height requirement :-

P(-2.58

Hence, the percentage of women meeting the height requirement = 99.51%

8 0
3 years ago
I'm dumb.
Arlecino [84]

1. \frac{1}{3}+\frac{1}{4}=\frac{4}{12}+\frac{3}{12}=\frac{7}{12}, assuming they mean pre eat values.

2. 44*(1-\frac{1}{4})=44*\frac{3}{4}=11*3=33

4 0
3 years ago
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