Answer:
3) 1 5/6 mi
4) a. 4 cm, 6 ft
b. 6.4 cm, 9.6 ft
c. same as part a
Step-by-step explanation:
3) Each of the given distances appears twice in the sum of side measures that is the perimeter. Hence by walking the perimeter twice, Kyle walks each of the given distances 4 times. His total walk is ...
4×1/3 + 4×1/8 = 4/3 + 4/8
= 1 1/3 + 1/2 = 1 2/6 + 3/6
= 1 5/6 . . . . . miles
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4) Since the figure is rectilinear (all angles are right angles, and all sides are straight lines), the sum of partial dimensions in one direction is equal to the whole dimension in that direction.
a. 8 cm = 4 cm + x
8 cm - 4 cm = x = 4 cm
The distance in the room is ...
(4 cm)×(1.5 ft/cm) = 6 ft
b. 10.3 cm = 3.9 cm + y
10.3 cm - 3.9 cm = y = 6.4 cm
The distance in the room is ...
(6.4 cm)×(1.5 ft/cm) = 9.6 ft
c. The answer to part b was obtained in the same way as the answer to part a. The unknown dimension is the difference of given dimensions. The actual length in the room is the model length multiplied by the inverse of the scale factor.
Answer:
Length = 42.5 cm
Step-by-step explanation:
length of rectangle = 5 + 3w
So l = 5 + 3w where w = 12.5
Equation:
L = 5 + 3(12.5)
Solving the Equation:
L = 5 + 3(12.5)
L = 5 + 36 + 1.5
L = 42.5
Length: 42.5 cm
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-Chetan K
2(15+N)
replace a number by N
replace the sum of 15 and N by (15+N)
and lastly, replace twice by 2
So your answer is 2(15+N)
The correct answer is B) No, because there is not a fixed number of trials.
