Question

There are 4 red and 6 green marbles in a jar. What is the probability of drawing two green marbles, with replacement?

Answer 1

The probability of drawing two green marbles, with replacement is $\frac{9}{25}$

Solution:

Given that There are 4 red and 6 green marbles in a jar

To find: probability of drawing two green marbles, with replacement

The probability of an event is given as:

$\text {probability }=\frac{\text { number of favourable outcomes }}{\text { total number of possible outcomes }}$

Here total number of possible outcomes = 4 red + 6 green marbles = 10

Favourable outcome is drawing two green marbles with replacement

So favourable outcome = 6

So probabilty of choosing green marble:

$probability = \frac{6}{10} = \frac{3}{5}$

Now given that with replacement, so we get

$\text { probability }=\frac{3}{5} \times \frac{3}{5}=\frac{9}{25}$

Thus probability is $\frac{9}{25}$