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Alekssandra [29.7K]
3 years ago
10

What is a Regression equation

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
6 0

Answer:

Regression equations can help you figure out if your data can be fit to an equation.This is extremely useful if you want to make predictions from your data- either future predictions or indications of past behavior.For example,you might want to know what your savings are going to be worth in the future.There are several types of regression equations,some of the more common include exponential and simoke linear regression.In elementary statistics,the regression equation you are most likely to come across is the linear form.

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Which of the following is an example of a rational number?
nexus9112 [7]
I’m sure it is b
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3 0
3 years ago
Al bought 24 stickers. He gave away 11 stickers. Then he bought 8 more stickers.
Yakvenalex [24]
24-11+8

He BOUGHT 24 stickers, so you'd write 24. Then because he GAVE AWAY 11 stickers, you would subtract 11 from 24, which is 24-11. Then because Al BOUGHT 8 stickers you'd add the 8 to the 24-11 to get 24-11+8.


(Bought means to add and Gave away is subtracting)
5 0
3 years ago
The temperature at a point (x, y) is T(x, y), measured in degrees Celsius. A bug crawls so that its position after t seconds is
aniked [119]

Answer:

10.50°C

Step-by-step explanation:

Given x = 2 + t , y = 1 + 1/2t where x and y are measured in centimeters. Also, the temperature function satisfies Tx(2, 2) = 9 and Ty(2, 2) = 3

The rate of change in temperature of the bug path can be expressed using the composite formula:

dT/dt = Tx(dx/dt) + Ty(dy/dt)

If x = 2+t; dx/dt = 1

If y = 1+12t; dy/dt = 1/2

Substituting the parameters gotten into dT/dt we will have;

dT/dt = 9(1)+3(1/2)

dT/dt = 9+1.5

dT/dt = 10.50°C/s

Hence the rate at which the temperature is rising along the bug's path is 10.50°C/s

7 0
3 years ago
Mindy is 36 years old. Mindy’s age is 3 years older than two times Jake’s age. Let j represent Jake’s age.
I am Lyosha [343]
J=30          !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
6 0
3 years ago
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Help ASAP. Thank you! Find the area of the shaded region.<br> 80°<br> 5 cm<br> A=[?] cm2
pashok25 [27]

Answer:

Step-by-step explanation:

\text{The area shaded outside of the triangle is}\\ \\ A=\frac{\pi r^2\theta}{360},\ r=5,\ \theta =80^o\\ \\ A=\frac{50\pi}{9}\\ \\ \text{Then we must add the area of the shaded triangle.}\\ \\ A=\frac{bh}{2}\\ \\ \frac{b}{2}=5sin40^o\\ \\ h=5cos40^o\\ \\ A=25sin40^o(cos40^o)\\ \\ \text{Total area is}\\ \\ A=\frac{50\pi }{9}+25sin40^o(cos40^o)\\ \\ A\approx 29.8cm^2

8 0
3 years ago
Read 2 more answers
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