Answer:
A change in pressure at any point in an enclosed fluid at rest is transmitted undiminished to all points in the fluid. With that said; in a hydraulic brake system, if the piston in the master cylinder(the part your foot pushes on) is one inch square area and you push with 100 pounds, then 100 pounds per square inch is transmitted to all parts of the hydraulic system. Now if the brake caliper piston(the part that pushes against the brake pad) is 2 square inches then there will be a total of 200 lbs of force being applied by the wheel cylinder, because each square inch has 100 pounds pushing on it. This is basically how cars brake systems are designed in order to reduce the amount of force required by the driver.
Btw if u want to give 67 points u must multiply that by 2 since two people answer and they get half of 67. Im still happy with my 34 though!
The enthalpy of fusion for Hg is 2.29 kJ/mol. 0.89 kJ is the energy change when 78.0 g of Hg melts at −38.8°C.
<h3>What is Enthalpy of Fusion ?</h3>
The amount of energy needed to change 1 mole of substance under state change at constant temperature and pressure is called enthalpy of fusion. It is also known as Latent heat of fusion. Unit of enthalpy of fusion is kJ/mol.
<h3>How to find the change in energy ? </h3>
To find the change in energy use this expression:
q = n ΔH
where
q = Energy change
n = number of moles
ΔH = Molar enthalpy
Number of moles (n) = 
= 
= 0.39 mol
Now put the values in above formula we get
q = n ΔH
= 0.39 mol × 2.29 kJ/mol
= 0.89 kJ
Thus from the above conclusion we can say that The enthalpy of fusion for Hg is 2.29 kJ/mol. 0.89 kJ is the energy change when 78.0 g of Hg melts at −38.8°C.
Learn more about the Latent heat of fusion here: brainly.com/question/87248
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Answer:
162g
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
2C2H6 + 7O2 —> 4CO2 + 6H2O
Next, we shall determine the number of mole of water, H2O produced by the reaction of 3 moles of C2H6.
This can be obtained as follow:
From the balanced equation above,
2 moles of C2H6 reacted to produce 6 moles of H2O.
Therefore, 3 moles of C2H6 will react to produce = (3 x 6)/2 = 9 moles of H2O.
Therefore, 9 moles of H2O is produced from the reaction.
Finally, we shall convert 9 moles of H2O to grams.
This can be done as shown below:
Molar mass of H2O = (2x1) + 16 = 18g/mol
Mole of H2O = 9 moles
Mass of H2O =..?
Mole = mass / molar mass
9 = mass of H2O /18
Cross multiply
Mass of H2O = 9 x 18
Mass of H2O = 162g
Therefore, 162g of H2O were produced from 3 moles of C2H6.
