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AleksAgata [21]
3 years ago
10

PLs help mweee Ill mark brainliest

Chemistry
1 answer:
Arturiano [62]3 years ago
7 0

the 3rd one is the answer

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I need help in chemistry 10th grade (sophomore)
Goryan [66]

Answer:

1) 2

2)4

3)5

4)2

5)2

6)1

7)3

8)5

9)4

10)4

11)3

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13)6

14)2

15)2

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3 0
3 years ago
Read 2 more answers
What labels in the areas marked Y and Z
MrMuchimi

Answer:

Can you please provide a graph or picture?

Explanation:

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3 0
3 years ago
A concrete pile from a waterfront pier was pulled from the harbor water at port hueneme california. It's dimensions we're 14in x
Anna [14]

The surface area expressed in square feet of a single face of a pile is 1.45 square feet.

<u>Explanation:</u>

The dimensions of the pillar are given as 14 in \times 14 in

(1 feet = 12 inch)

According to the pillar dimensions mentioned in the problem, the length of the pillar should be 15 inches, height by 14 inches and the width by 14 inches.

There will be two surface areas of the concrete pile, one implies side surface area and the other is end surface area.

For calculating the side surface area,

Area of the side surface = 14 in \times 15 in

                                         = 14 in. \times  \frac{1 ft.}{12 in.}

                                         = 1.16 \times 1.25

                                         = 1.45 square feet.

(In the given question, only a single face is asked so there is no need to find the surface area of the end face.)

8 0
3 years ago
When N,N-Dimethylaniline is treated with bromine, ortho and para products are observed. However, when N,N-Dimethylaniline is tre
lilavasa [31]

Answer:

See explanation below

Explanation:

To get a better understanding watch the picture attached.

In the case of the reaction with Bromine, the -N(CH₃)₂ is a strong ring activator, therefore, it promotes a electrophilic aromatic sustitution, so, in the mechanism of reaction, the lone pair of the Nitrogen, will move to the ring by resonance and activate the ortho and para positions. That's why the bromine wil go to the ortho and para positions, mostly the para position, because the -N(CH₃)₂ cause a steric hindrance in the ortho position.

In the case of the reaction with HNO₃/H₂SO₄, the acid transform the -N(CH₃)₂ in a protonated form, the anilinium ion, which is a deactivating of the ring, and also a strong electron withdrawing, so, the electrophile will go to the meta position instead.

Hope this helps.

6 0
2 years ago
What will happen If CH4 is added to the following reaction at equilibrium CH4 (g) + 2H2O (g) &lt;------&gt; 3H2 (g) + CO2 (g)
inysia [295]

Answer:

the answer is D  

:)

:D

Explanation:

6 0
3 years ago
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